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 B.Sc

GENERAL CHEMISTRY-III

NEW REGULATION

FOR III SEMESTER B.Sc CHEMISTRY MAJOR STUDENTS

ENGLISH MEDIUM

 

அனைத்து பல்கலைகழக மாணவர்களுக்கும் பொதுவானது

 

இரா.மணிமாறன்

விரிவுரையாளர்

வேதியியல் துறை

அரசினர் திருமகள் ஆலைக்கல்லூரி, குடியாத்தம்

 

 

 

MS

மாறா  பப்ளிஷர்ஸ்


பதிப்புரிமை © 2024 இரா.மணிமாறன்

முதல் பதிப்பு: 2024

அனைத்து உரிமைகளும் பாதுகாக்கப்பட்டவை.

இந்த புத்தகம் ஆசிரியரின் பொருள் பிழையின்றி செய்ய எடுக்கப்பட்ட அனைத்து நியாயமான முயற்சிகளுடன் சுயமாக வெளியிடப்பட்டது. விமர்சனக் கட்டுரைகள் மற்றும் மதிப்புரைகளில் பொதிந்துள்ள சுருக்கமான மேற்கோள்களைத் தவிர, இந்தப் புத்தகத்தின் எந்தப் பகுதியும், ஆசிரியரின் எழுத்துப்பூர்வ அனுமதியின்றி, எந்த வகையிலும் மீண்டும் உருவாக்கப்படக் கூடாது.

பார்வைகள், பிரதிநிதித்துவங்கள், விளக்கங்கள், அறிக்கைகள், தகவல், கருத்துகள் மற்றும் குறிப்புகள் [“உள்ளடக்கம்”] உட்பட ஆனால் இவற்றுடன் மட்டுப்படுத்தப்படாத உள்ளடக்கத்திற்கு இந்தப் புத்தகத்தின் ஆசிரியர் முழுப்பொறுப்பு. இந்தப் புத்தகத்தின் உள்ளடக்கம், பதிப்பாளர் அல்லது ஆசிரியரின் கருத்து அல்லது வெளிப்பாட்டை பிரதிபலிக்கும் வகையில் கட்டமைக்கப்பட கூடாது.

 

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ISBN: 978-81-966729-7-3

    


CONTENT

UNIT I. 1

1.       Gaseous state. 1

1.1.  Kinetic molecular model of a gas: 2

1.2.  postulates and derivation from the kinetic gas equation; 6

1.3.  Maxwell –Boltzmann distribution of speed of molecules. 7

1.4.  Average. 9

1.5.  Root mean square. 10

1.6.  Most probable velocity and average kinetic energy. 11

1.7.  law of equipartition of energy. 12

1.8.  Degrees of freedom.. 13

1.9.  Collision frequency. 13

1.10.         collision diameter 14

1.11.         mean free path. 15

1.12.         Deviations from ideal gas behaviour, (Andrew’s and Amagat’s plots); 18

1.13.         compressibility factor, Z, and its variation with pressure for different gases. 23

1.14.         Equations of states for real gases-van der Waal’s equation  24

1.15.         Virial equation; Boyle temperature. 26

1.16.         Numerical problems based on equations of states for real gases  27

ISOTHERMS OF REAL GASES. 32

1.17.         critical phenomena – isotherms of CO2. 32

1.18.         Van der waal’s equation and the critical state. 34

1.19.         Liquefaction of gases. 37

1.20.         QUESTIONS. 39

UNIT-II. 40

2.       Liquid and Solid State. 40

2.1.  Properties of Liquids. 40

2.2.  Surface tension, viscosity and their applications. 40

2.3.  Crystalline and amorphous. 47

2.4.  Differences - geometry, isotropy and anisotropy, melting point; 47

2.5.  isomorphism, polymorphism. 48

2.6.  Crystals –size and shape; 53

2.7.  laws of crystallography; 56

2.8.  symmetry elements – plane, centre and axis; Miller indices  58

2.9.  Unit cells and space lattices. 61

2.10.         classification of crystal systems. 62

2.11.         Bravais lattices. 63

2.12.         X – ray diffraction. 63

2.13.         Bragg’s equation. 64

Packing in atomic solids. 66

2.14.         simple cubic. 66

2.15.         body centered cubic. 67

2.16.         face centered cubic. 67

2.17.         hexagonal close packing. 68

2.18.         Co-ordination number in typical structures NaCl, CsCl, ZnS, TiO2  70

2.19.         comparison of structure and properties of diamond and graphite  71

2.20.         numerical problems involving core concepts. 73

2.21.         Defects in solids –. 74

2.22.         stoichiometric defects. 75

2.23.         Non-stoichiometric defects. 77

2.24.         Liquid crystals. 79

2.25.         classification and applications. 81

UNIT-III 87

3.       Nuclear Chemistry. 87

3.1.  Natural radioactivity - α, β and ɣ rays. 87

3.2.  Half-life period. 87

3.3.  Fajan–Soddy group displacement law.. 90

3.4.  Geiger–Nattal rule. 91

3.5.  isotopes, isobars, isotones. 94

3.6.  Mirror nuclei 95

3.7.  iso diaphers. 96

3.8.  Nuclear isomerism.. 97

3.9.  radioactive decay series. 98

3.10.         magic numbers. 103

3.11.         Units. 106

3.12.         nuclear stability - neutron- proton ratio. 107

3.13.         Binding energy. 109

3.14.         Packing fraction. 112

3.15.         Mass defect. 113

3.16.         Simple calculations involving mass defect and B.E., decay constant and t1/2 and radioactive series. 114

3.17.         Isotopes – uses. 119

3.18.         Nuclear energy; nuclear fission and fusion. 120

3.19.         major nuclear reactors in India. 124

3.20.         Radiation hazards, disposal of radioactive waste and safety measures. 125

UNIT-IV.. 136

4.       Halogen derivatives Aliphatic halogen derivatives. 136

4.1.  Nomenclature and classes of alkyl halides. 137

4.2.  Physical properties. 139

4.3.  Chemical reactions. Nucleophilic substitution reactions – SN1, SN2 and SNi mechanisms with stereochemical aspects and effect of solvent. 141

4.4.  Di, Tri & Tetra Halogen derivatives: 150

4.5.  Preparation. 151

4.6.  Properties. 152

4.7.  Aromatic halogen compounds. 161

4.8.  Nomenclature. 161

4.9.  Preparation. 162

4.10.         Properties. 164

4.11.         Uses. 168

4.12.         Mechanism of nucleophilic aromatic substitution – benzyne intermediate. 169

4.1.  Aryl alkyl halides Nomenclature. 175

4.2.  Alcohols. 177

4.3.  Nomenclature. 178

4.4.  Classification. 180

4.5.  Preparation. 181

4.6.  Properties. 184

4.7.  Uses. 187

4.8.  Test for hydroxyl groups. 188

4.9.  Oxidation of diols by periodic acid. 190

4.10.         Oxidation of diols by lead tetraacetate. 191

UNIT-V.. 193

5.       Phenols. 193

5.1.  Nomenclature; 193

5.2.  Preparation from diazonium salts. 194

5.3.  Preparation from Cumene. 194

5.4.  Dow’s process. 194

5.5.  Raching process; 195

5.6.  Properties. 196

5.7.  acidic character and effect of substitution on acidity. 198

5.8.  Fries Rearrangement 200

5.9.  Claisen rearrangement 202

ELECTROPHILIC SUBSTITUTION REACTIONS. 205

5.10.         Reimer – Teimen Reaction. 205

5.11.         Kolbe-Schmidt Reaction. 205

5.12.         Gatermann synthesis. 206

5.13.         Libermann reaction. 207

5.14.         phthalein reaction. 207

5.15.         Resorcinol 208

5.16.         Quinol 211

5.17.         picric acid. 213

5.18.         Aromatic alcohols Nomenclature. 216

5.19.         Benzyl alcohol 217

METHODS OF PREPARATION.. 218

5.20.         HYDROLYSIS. 218

5.21.         Reduction of benzaldehyde. 218

5.22.         Cannizzaro reaction. 219

5.23.         Grignard synthesis. 221

5.24.         Physical properties. 221

5.25.         Thiols. 224

Model Question Paper 228


UNIT I

1.    Gaseous state

Amongst the three common states of matter, the gaseous state is simplest. The laws of gaseous behaviour are more uniform and are better understood. The well known laws of gaseous behaviour are Boyle’s law, Charle’s law Graham’s law, Dalton’s law and Avogadro’s law. There was no theoretical background to justify them. In the nineteenth century, however, Kronig, Clausius, Maxwell and Boltzmann developed a theory known as kinetic molecular theory of gases, which provided sound theoretical basis for the various gas laws.

There are two opposite molecular forces, the forces of attraction and the disruptive forces operating between molecules. If the thermal energy is much greater than the forces of attraction, then we have matter in its gaseous state.

In contrast with solids and liquids gases occupy the same volume as that of the closed vessel, they are characterised by low density and high compressibility.

The characteristic properties of gases are given below.

1.     No definite shape and volume: Gases occupy all available space i.e. the shape and volume of the container in which they are filled.

2.     Expansibility: Gases have limitless expansibility. They expand to fill the entire vessel they are placed in.

3.     Compressibility: Gases are easily compressed by application of pressure.

4.     Diffusibility: Gases can diffuse rapidly through each other to form a homogeneous mixture.

5.     Pressure: Gases exert pressure on the walls of the container in all direction. You can site the example of a gas balloon.

6.     Effect of heat: When a gas confined in a vessel is heated, its pressure increases. Upon heating in a vessel fitted with a piston, volume of the gas increases.

1.1. Kinetic molecular model of a gas:

Suppose a volume of gas enclosed in a cubical vessel at a fixed temperature.

Suppose that :


the length of each side of cube = l cm

the number of gas molecules = n the mass of one molecule   = m

the velocity of a molecule  = υ

Let us consider one single molecule of a gas can be evaluated by calculating the momentum during collisions.

According to kinetic model the molecules of the gas are moving in straight lines in all possible directions. They collide with one another frequently as also with the walls of the container. Since their mutual collisions are perfectly elastic and do not involve the loss of energy, these may be neglected. Here we will, therefore, assume that gas molecules move in all directions but rebound whenever they strike the wall of the container. Now you proceed to derive kinetic gas equation in the following steps

According to the kinetic theory', a molecule of a gas can move with velocity in any direction velocity is a vector quantity can be resolved into components υx, υy, υz along the X, Y and Z axes. These components are related to velocity υ by the following expression.

Let us consider a molecule moving in ox direction between opposite faces A and B. It will strike the face A with velocity υx and rebound with velocity -υx. To hit the same face again the molecule must travel l cm to

Collide with opposite face B and then again l cm to return to face A. Therefore, time taken between two collisions can be calculated as follows

The molecule travels .x cm in 1 sec

·       hence 1 cm in 1/υx sec

·       And 2l cm in 2l/υx sec…………………………. (2)

·       In 2l/υx sec molecule suffers 1 collision

·       In 1 sec no of collisions = υx/2l………………… (3)

Each impact of the molecule on the face A causes a change of momentum which is mass x velocity.

·       Momentum of the molecule before impact = mυx

·       Momentum of the molecule after impact = - mυx

·       Hence change of momentum = m.x - (-m.x) = 2mυx

·       But the number of collision per second on face A= υx/2l

Therefore total change of momentum per second on face A caused by one Molecule      = 2m/x x υx/2l

= mυx2/l………………. (4)

As there are two faces along x- direction, total change of momentum per second considering both the faces along x-direction will be

2mυx2/l………………. (5)

This is change of momentum caused by one molecule along x-direction. The change of momentum caused by one molecule along y- direction per second will be 2mυ2/l and change of momentum caused by one molecule along z-direction per second will be 2mυ2 /l

Total change of momentum caused by one molecule considering along three directions will be

2mυx2/l + 2mυy2/l + 2mυ2/l

= 2m/l (υx2+υy2+υz2)

= 2mυ2/l………………….(6)

Since there are n molecules in the vessel then total change of momentum due to n molecules will be

2mnυ2/l…………………...(7)

υ2= mean square velocity

Since change of momentum per second is force

Hence force            = 2mnυ2/2

Since pressure         = Total force/Total area

Since there are six faces in a cube, area of each cube is l2. Hence total area is 6l2

Then pressure         = 2mnυ2/l x 1/6l2

= mnυ2/3l2

As                          l2 = volume V

Hence pressure       P= 1/3 mnυ2/V…………….(8)

This is known as Kinetic gas equation. This equation has been derived for a cubical vessel. It is equally valid for vessel of any shape. The available volume in the vessel may be considered as made up of large number of infinitesimally small cubes, for each of them the equation is valid.

1.2. postulates and derivation from the kinetic gas equation;

Boyle’s law

From his observations Boyle’s in 1660 formulated a generalisation known as Boyle’s law. Boyle’s law states that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure.

According to kinetic theory, kinetic energy is directly proportional to temperature (in absolute scale).

Charle’s law : for a definite quantity of gas at constant pressure, its volume is directly proportional to the absolute temperature. It was established in 1787.

From above discussion V= 2/3 KT/P

At constant pressure V= constant xT Or V α T  when P is constant.

This is Charle’s law

Avogadro’s law:  It is states that equal volume of gases at same temperature and pressure contain equal number of molecules.

Suppose there are two gases for first gas mass of one molecule is m1, velocity is υ1 and number of molecules are n1. And for the second gas mass of one molecule is m2, velocity is υ2 and number of molecules are n2

1.3. Maxwell –Boltzmann distribution of speed of molecules

In a classroom, the air molecules are moving in random directions. The speed of each molecule is not the same even though macroscopic parameters like temperature and pressure are fixed.  Each molecule collides with every other molecule and they exchange their speed.

we calculated the rms speed of each molecule and not the speed of each molecule which is rather difficult. In this scenario we can find the number of gas molecules that move with the speed of 5 ms-1 to 10 ms-1 or 10 ms-1 to 15 m s-1 etc. In general our interest is to find how many gas molecules have the range of speed from 𝛎  to 𝛎 + d𝛎. This is given by Maxwell’s speed distribution function.

The above expression is graphically shown as follows

From the Figure it is clear that, for a given temperature the number of molecules having lower speed increases parabolically

(𝛎2) but decreases exponentially after reaching most probable speed. The rms speed, average speed and most probable speed are indicated in the Figure. It can be seen that the rms speed is greatest among the three.

To know the number of molecules in the range of speed between 50 m s−1 and 60 m s−1, we need to integrate    =N(50 to 60 ms-1). In general the number of molecules within the range of speed v and v+dv is given by

But we can infer the behavior of gas molecules from the graph.

(i)              The area under the graph will give the total number of gas molecules in the system

(ii)            Figure shows the speed distribution graph for two different temperatures.

As temperature increases, the peak of the curve is shifted to the right.

It implies that the average speed of each molecule will increase. But the area under each graph is same since it represents the total number of gas molecules.

1.4.              Average

It is defined as the mean (or) average of all the speeds of molecules

If 𝛎 1, 𝛎 2, 𝛎 3………. 𝛎 N are the individual speeds of molecules then

 Here M- Molar Mass and m – mass of the molecule.

1.5. Root mean square

Root mean square speed (𝛎 rms) is defined as the square root of the mean of the square of speeds of all molecules. It is denoted by 𝛎 rms

From the equation we infer the following

(i)  rms speed is directly proportional to square root of the temperature and inversely proportional to square root of mass of the molecule. At a given temperature the molecules of lighter mass move faster on an average than the molecules with heavier masses.

Example: Lighter molecules like hydrogen and helium have high ‘vrms’ than heavier molecules such as oxygen and nitrogen at the same temperature.

(ii)  Increasing the temperature will increase the r.m.s speed of molecules We can also write the vrms in terms of gas constant R.  Equation can be rewritten as follows  Where NA is Avogadro Number.

Since NAk = R and NAm = M (molar mass) The root mean square speed or r.m.s speed

The equation can also be written in terms of rms speed

Impact of v in nature:

Moon has no atmosphere.

The escape speed of gases on the surface of Moon is much less than the root mean square speeds of gases due to low gravity. Due to this all the gases escape from the surface of the Moon.

No hydrogen in Earth’s atmosphere.

As the root mean square speed of hydrogen is much greater than that of nitrogen, it easily escapes from the earths atmosphere.

In fact, the presence of nonreactive nitrogen instead of highly combustible hydrogen deters many disastrous consequences.

1.6. Most probable velocity and average kinetic energy

The average kinetic energy of gas molecules is directly proportional to absolute temperature. This means that the average kinetic energy of molecules is the same at a given temperature.

This must be clear to you that all the above postulates are applicable to ideal gases only i.e. the gas which obey Boyle’s and Charle’s law under all conditions of temperature and pressure. These are only approximately valid for real gases.

1.7. law of equipartition of energy

 The average kinetic energy of a molecule moving in x direction is

 and for the motion along z direction,

According to kinetic theory, the average kinetic energy of system of molecules in thermal equilibrium at temperature T is uniformly distributed to all degrees of freedom (x or y or z directions of motion) so that each degree of freedom will get ½ kT of energy. This is called law of equipartition of energy.

Average kinetic energy of a monatomic molecule (with  f=3)  Average kinetic energy of diatomic molecule at low temperature (with f = 5)  Average kinetic energy of a diatomic molecule at high temperature (with f =7)

Average kinetic energy of linear triatomic molecule (with f = 7) Average kinetic energy of non linear triatomic molecule (with f = 6)

1.8. Degrees of freedom

The minimum number of independent coordinates needed to specify the position and configuration of a thermo-dynamical system in space is called the degree of freedom of the system.

Example:

A free particle moving along x-axis needs only one coordinate to specify it completely. So its degree of freedom is one.

Similarly, a particle moving over a plane has two degrees of freedom.

A particle moving in space has three degrees of freedom.

Suppose if we have N number of gas molecules in the container, then the total number of degrees of freedom is f = 3N.

But, if the system has q number of constraints (restrictions in motion) then the degrees of freedom decreases and it is equal to f = 3N-q where N is the number of particles.

1.9. Collision frequency

The collision frequency of a gas is defined as: The number of collisions taking place per second per unit volume (c.c.) of the gas.

Let a gas contain N molecules per cc. From kinetic considerations it has been established that the number of molecules, n, with which a simple molecule will collide per second, is given by the relation

where υa = average velocity and σ =collision diameter.

If the total number of collisions taking place per second is denoted by z we have

Since each collision involves two molecules, the number of collision per second per cc, of the gas will be z/2 Hence the collision frequency

Evidently, the collision frequency of a gas increases with increase in temperature, molecular size and the number of molecules per c.c.

1.10.            collision diameter

The kinetic theory of gases treats molecule as point masses. When two such molecules approach each other, a point is reached at which they cannot come closer beyond a certain distance.

The closest distance between the centres of the two molecules taking part in collision is called the collision diameter. It is denoted by σ.

Whenever the distance between the centres of two molecules is σ, a collision occurs. The collision diameter can be determined from viscosity measurements. The collision diameter of  hydrogen is 2.74 Å and that of oxygen is 3.61 Å

1.11.             mean free path

Usually the average speed of gas molecules is several hundred meters per second even at room temperature (27°C). Odour from an open perfume bottle takes some time to reach us even if we are closer to the room. The time delay is because the odour of the molecules cannot travel straight to us as it undergoes a lot of collisions with the nearby air molecules and moves in a zigzag path. This average distance travelled by the molecule between two successive collisions is called mean free path (λ). We can calculate the mean free path based on kinetic theory.

Expression for mean free path We know from postulates of kinetic theory that the molecules of a gas are in random motion and they collide with each other.

Between two successive collisions, a molecule moves along a straight path with uniform velocity. This path is called mean free path.

Consider a system of molecules each with diameter d. Let n be the number of molecules per unit volume.

Assume that only one molecule is in motion and all others are at rest

If a molecule moves with average speed v in a time t, the distance travelled is vt. In this time t, consider the molecule to move in an imaginary cylinder of volume πd2vt. It collides with any molecule whose center is within this cylinder. Therefore, the number of collisions is equal to the number of molecules in the volume of the imaginary cylinder. It is equal to πd2 vtn. The total path length divided by the number of collisions in time t is the mean free path.

Though we have assumed that only one molecule is moving at a time and other molecules are at rest, in actual practice all the molecules are in random motion. So the average relative speed of one molecule with respect to other molecules has to be taken into account.

After some detailed calculations (you will learn in higher classes) the correct expression for mean free path

The equation implies that the mean free path is inversely proportional to number density. When the number density increases the molecular collisions increases so it decreases the distance travelled by the molecule before collisions.

Case1: Rearranging the equation using ‘m’ (mass of the molecule)

But mn=mass per unit volume = ρ (density of the gas)

Also we know that PV = NkT

 

The equation implies the following

1. Mean free path increases with increasing temperature. As the temperature increases, the average speed of each molecule will increase. It is the reason why the smell of hot sizzling food reaches several meter away than smell of cold food.

2. Mean free path increases with decreasing pressure of the gas and diameter of the gas molecules.

 

1.12.            Deviations from ideal gas behaviour, (Andrew’s and Amagat’s plots);

An ideal gas is one which obeys the gas laws for the equation PV = RT at all pressures and temperatures. However, no gas is ideal. They approach perfection as the temperature gets farther from their boiling points. Thus the gases H2, N2 and CO2 which fail to obey the ideal-gas equation are termed as non ideal or real gases

The extent to which a real gas depart from ideal behaviour may be depicted in terms of a function called compressibility factor, denoted by Z.

It is defined

Z = PV/RT

The deviation from ideality may be shown by a plot of compressibility factor, Z against P.

For an ideal gas Z =1. For real gases the deviation from ideal behaviour will be determined by the value of Z being greater or less than unity.

Andrews in 1869 determined the isotherm of carbon dioxide at different temperatures.

The isotherms of carbon dioxide determined by him at different temperature. Consider the first Isotherm at 13.10C.

The point A represents carbon di-oxide in the gaseous state occupying a certain volume under a certain pressure. On increasing the pressure its volume diminishes as is indicated by the curve AB. At B liquification of gas commences and there after a rapid decrease in volume takes place at the same pressure as more and more of gas is converted into the liquid state. At C, the gas has been completely liquified. Now, as the liquid is only slightly compressible further increase of pressure produces only a very small decrease in volume. This is shown by a steep line CD which is almost vertical.

Thus along AB, carbon dioxide exists as gas; along BC, it exists partly as gas and partly as liquid while along CD, it exists entirely as liquid.

The curve EFGH at 21.50C shows a similar behaviour except that now the liquification commences at higher pressure and the horizontal portion FG, representing decrease in volume, becomes smaller. At still higher temperature, the horizontal portion of the curve becomes shorter and shorter until at 31.10C it reduces just to a point represented by X.

The curve passing through this point X marks the boundary between gaseous carbon dioxide and on the right and liquid carbon dioxide on the left.

Andrews noted that above 31.10C there was no possibility of liquefaction of carbon dioxide how great the pressure is applied. At this temperature the gas is in critical state. The point X is then called the critical point. The isotherm passing through this point is called the critical isotherm and the temperature corresponding to this isotherm (31.10C) is called critical temperature.

The critical phenomenon observed by Andrews in connection with carbon dioxide may be observed with any other gas. The pressure required to liquefy the gas at critical temperature is called the critical pressure and the volume occupied by one mole of the gas under these conditions is called critical volume.

It is possible to convert liquid carbondioxide into gas and vice-versa, without any discontinuity that is without having at any time more than one phase present, on joining the end of the horizontal portion of the various isotherm, a bonding curve CGXFB represented by the dotted line is obtained. At the top lies the critical point X, with in the area of the boundary curve, both liquid and gaseous state can coexist but outside this area either liquid or gaseous state alone can exist. Because of this coexistence curve, it is possible to distinguish between the two states of matter, namely, gas and liquid. However, in practice this is not always true because it is possible to convert matter from one state into another without any sharp discontinuity.

(i) Increase the temperature of the gas keeping volume constant. The pressure rises along xy.

(ii) Having reached y, the pressure is kept constant and the gas is cooled; this decrease the volume along the line yz.

Thus we have passed from x to z without the gradual change as it occurs along the line BC, ie condensation in the usual sense of the term did not occur. Point 2 could be said to represent a highly compressed gaseous state of the substance. Whether we refer to the state in the region of point z as liquid state or as highly compressed gaseous state depends purely upon which of the two view points happens to be convenient at the moment.

Thus, in the absence of the surface of discontinuity, there is no way of distinguishing between liquid and gas. Von der Waals equation and critical state Thomas in 1871 studied the isotherms of carbon dioxide drawn by Andrews. He suggested that there should be no sharp points in the isotherms below the critical temperature. These isotherms should really exhibit a complete continuity of state from gas to liquid. This he showed by a theoretical wavy curve.

The curve MLB represents a gas compressed in a way that would remain stable. The curve MNC represents a superheated liquid. This type of discontinuity of state is predicted by von der Waals cubic equation.

According to it, for any given values of P and T there should be three values of v. These values are indicated by B, M and C of the curve. The three values of v become closer as the horizontal part of the isotherm. At the critical point, these values become identical.

This enables the calculation of critical temperature, critical pressure and critical volume in terms of von der Waals constants.

The actual determination of critical constants is often a task of considerable difficulty of these critical pressure and critical temperature can be measured relatively easily with the help of Cagniard de la Tour’s apparatus. The most accurate method for determining critical volume in due to Amagat.

1.13.            compressibility factor, Z, and its variation with pressure for different gases.

An ideal gas is one which obeys the gas laws for the equation PV = RT at all pressures and temperatures. However no gas is ideal. They approach perfection as the temperature gets farther from their boiling points. Thus the gases H2, N2 and CO2 which fail to obey the ideal-gas equation are termed as non ideal or real gases

The extent to which a real gas depart from ideal behaviour may be depicted in terms of a function called compressibility factor, denoted by Z.

It is defined

Z = PV/RT

The deviation from ideality may be shown by a plot of compressibility factor, Z against P.

For an ideal gas Z =1. For real gases the deviation from ideal behaviour will be determined by the value of Z being greater or less than unity.

Effect of pressure

The compressibility factor Z, plotted against pressure for H2, N2 and CO2 at constant temperature.

At very low pressure for all these gases Z is approximately one. This indicates that all real gases exhibit ideal behaviour (upto 10 atm). For hydrogen curve lies above ideal gas curve at all pressure.

For nitrogen and carbon di-oxide, Z first decreases. It passes to a minimum then increases continuously with increase of pressure. For gas like CO2 the dip in the curve is greatest as it is most easily liquified.

1.14.           Equations of states for real gases-van der Waal’s equation

Von der Waal’s 1873 studied the postulates of kinetic theory in detail and found that there are two faulty postulates.

(i) The molecules in a gas are point masses and possess no volume. (ii) There are no intermolecular attractions in a gas.

Von der Waal’s was the first to introduce systematically the correction terms due to the above two invalid assumptions in the ideal gas equation PV = nRT.

His corrections are given below.

Volume correction

Volume of the gas in the available space for the movement of gas molecules. Volume V of an ideal gas is the same as the volume of the container. The dot molecule of ideal gas has zero-volume and the entire space in the container is available for their movement.

But von der Waals assume that molecules of real gas are rigid spherical particles which posses a definite volume. The volume of real gas is, therefore ideal volume minus the volume occupied by gas molecules. If b is the effective volume of molecules per mole of the gas then corrected volume should be V-b = Videal For n moles Videal = V-nb b is also known as excluded volume.

Now let us consider two molecules of radius r colliding with each other Obviously they cannot approach each other closer than a

1.15.            Virial equation; Boyle temperature

Experiments of Andrews, Amagat and others show that no gas obeys Boyle’3 law except over a very restricted range. Kamerling Onnes observed that the behaviour of real gases can be expressed by an empirical equation of the form

pV = A + Bp + Cp2 + Dp3 + ……

where the coefficients A, B,C,D, …. are functions of temperatures and are called virial coefficients - A is the first virial coefficient, B the second virial coefficient etc. For a given temperature, however, they are constants characteristic of the fluid concerned. The coefficients decrease rapidly for higher terms so that C, D, …. etc. are small and the terms involving them become important only at very high pressures.

Plainly, the first virial coefficient A = RT, since for p 0, equation should reduce to the ideal gas equation for one mole of the gas.

The second virial coefficient B is particularly important. For all gases, it varies in a similar way and at very low temperatures, it has a large negative value, increases gradually to zero with rise in temperature and finally becomes positive. At room temperature, B < 0 for O2, N2 and CO2 and B > 0 for H2 and He.

If at any temperature, B - 0, then neglecting C, D, etc. which are very small, we get from equation   pV = const. = A = RT

and the Boyle’s law is obeyed over a wide range of pressure. The temperature at which the value of the second virial coefficient B vanishes is the Boyle temperature or Boyle point. One may as well any that the Boyle temperature is the temperature at which B changes sign.

while ordering Amagat’s   how the concept of boyle temperature originated. At moderate and low pressures, it is sufficient to retain only the first two terms of the equation

pV = A + Bp

As p →0, pV →A end the gM obeys Boyle’s law more and more accurately Th, correction to gas scale thermometers is usually made through equation

1.16.            Numerical problems based on equations of states for real gases

Problem 1

Calculate the partial pressures N2 and H2 in a mixture of two moles of N2 and two moles of H2 at STP.

Problem 2

If a gas diffuses at the rate of one-half as fast as O2, find the molecular mass of the gas.

Solution

Applying Graham's law of diffusion.

Problem 3

50ml of gas A effuse through a pin - hole in 146 seconds. The same volume of CO2 under identical conditions effuse in 115 seconds. Calculate the molecular mass of A.

Problem 4

One mole of carbon-dioxide was found to occupy a volume of 1.32 litre at 48°C and at a pressure of 16.4 atm. Calculate the pressure of the gas that would have been expected to behave ideally and non-ideally.

Problem 5

Vanderwaal's constants for hydrogen chloride gas are a = 3.67 atm lit-2 and b = 40.8 ml mol-1. Find the critical temperature and critical pressure of the gas.

Problem 6

The critical temperature of hydrogen gas is 33.2°C and its critical pressure is 12.4 atm. Find out the values of 'a' and 'b' for the gas.

ISOTHERMS OF REAL GASES

1.17.            critical phenomena – isotherms of CO2

Thomas Andrew gave the first complete data on pressure-volume- temperature of a substance in the gaseous and liquid states. He plotted isotherms of carbon dioxide at different temperatures. From the plots we can infer the following.

At low temperature isotherms, for example, at 130C as the pressure increases, the volume decreases along AB and is a gas until the point B is reached. At B, a liquid separates along the line BC, both the liquid and gas co-exist and the pressure remains constant. At C, the gas is completely converted into liquid. If the pressure is higher than at C, only the liquid is compressed so, there is no significant change in the volume.

The successive isotherms shows similar trend with the shorter flat region. i.e. The volume range in which the liquid and gas coexist becomes shorter. At the temperature of 31.10C the length of the shorter portion is reduced to zero at point P. In other words, the CO2 gas is liquefied completely at this point.

This temperature is known as the liquefaction temperature or critical temperature of CO2. At this point the pressure is 73 atm. Above this temperature CO2 remains as a gas at all pressure values. It is then proved that many real gases behave in a similar manner to carbon dioxide.

Though the nature of isotherm remains similar, the critical temperature, the corresponding pressure and volume are characteristics of a particular gas.

Now we can define the critical constants as follows. Critical temperature (Tc) of a gas is defined as the temperature above which it cannot be liquefied even at high pressure. Critical pressure (Pc) of a gas is defined as the minimum pressure required to liquefy 1 mole of a gas at its critical temperature. Critical volume (Vc) is defined as the volume occupied by 1 mole of a gas at its critical temperature and critical pressure. The critical constants of some common gases are given in Table.

Name of the Gas

Critical Temperature (T) in K

Critical Pressure (Pc) in atm

Critical Volume (Vc) cm3 mol-1

Helium (He)

5.2

2.26

57.8

Carbon dioxide(CO2)

304.2

72.9

94.0

Oxygen (O2)

154.8

50.14

78.0

Nitrogen (N2)

126.3

33.54

90.1

Hydrogen (H2)

33.2

12.80

65

Water (H2O)

647.4

218.3

55.3

Ammonia (NH3)

405.5

111.3

72.5

Hydrogen Chloride (HCl)

324.7

81.5

81.0

Methane (CH4)

190.6

45.6

98.7

Ethylene (C2H4)

283.1

50.50

124

 

1.18.            Van der waal’s equation and the critical state

The van der Waals equation  for n moles is

For 1 mole

From the equation we can derive the values of critical constants Pc, Vc and Tc in terms of a and b, the van der Waals constants, On expanding the above equation

Multiply equation by V2 / P

When the above equation is rearranged in powers of V

The equation is a cubic equation in V. On solving this equation,

we will get three solutions. At the critical point all these three solutions of V are equal to the critical volume VC. The pressure and temperature becomes Pc and Tc respectively

we can equate the coefficients of V2, V and constant terms

             

substituting the values of V and Pc

The critical constants can be calculated using the values of van der waals constant of a gas and vice versa.

1.19.            Liquefaction of gases

For important commercial operations such as LPG and rocket fuels, we require gases in their liquid state.

The liquefication methods are based on the Joule-Thomson effect. He observed appreciable cooling when the compressed gas is forced through an orifice plug into a low-pressure region. This phenomenon of lowering of temperature when a gas is made to expand adiabatically from a region of high pressure into a region of low pressure is known as Joule- Thomson effect. This effect is observed only below a certain temperature, which is a characteristic one for each gas. This temperature below which a gas obeys Joule-Thomson effect is called inversion temperature (Ti). This value is given using van der waals constants a and b.

Gases like O2, He, N2 and H2 have very low T, hence Joule-Thomson effect can be applied for cooling effectively At the inversion temperature, no rise or fall in temperature of a gas occurs while expanding. But above the inversion temperature, the gas gets heated up when allowed to expand through a hole.

There are different methods used for liquefaction of gases:

In Linde’s method, Joule-Thomson effect is used to get liquid air or any other gas.

In Claude’s process, the gas is allowed to perform mechanical work in addition to Joule-Thomson effect so that more cooling is produced.

In Adiabatic process, cooling is produced by removing the magnetic property of magnetic material such as gadolinium sulphate. By this method, a temperature of 10-4 K i.e. as low as 0 K can be achieved.

Conditions of liquefaction of gases

Many industrial processes require large quantities of liquid air, liquid ammonia, liquid carbondioxide etc. The production of liquids from various gases is therefore an important commercial operation.

There are different methods of liquefaction of gases, such as (i) based on the concept of critical temperature followed by the compression (ii) based on Joule-Thomson effect (iii) Adiabatic demagnetisation.

In the case of gases like NH3, Cl2, SO2 and CO2 whose Tc values are near and below the ordinary temperatures, they can be liquefied easily by increasing the pressure alone at their respective Tc values.

Gases like H2, O2, N2 and He have very low Tc values and hence Joule Thomson effect may be applied to bring in effective cooling.

Helium is cooled by Joule-Thomson effect to a lower temperature and further cooling for its liquefaction, is carried out by the method of adiabatic demagnetisation.

 

1.20.           QUESTIONS

1.     Write the mathematical expression for Boyle's law.

2.     Compare the partial pressures of gases A and B when 3 moles of A and 5 moles of B mixed in constant volume, and 25oC and 1 atm pressure.

3.     Give the correction factors for the volume and pressure deviation for a Vanderwaal's gas.

4.     A sample of an ideal gas escapes into an evacuated container, there is no change in the kinetic energy of the gas. Why?

5.     What is the change in temperature when a compressed real gas is allowed to expand adiabatically through a porous plug.

6.     Define Boyle's law and Charle's law.

7.     What are measurable properties of gases?

8.     What is the molar volume of nitrogen at 500K and 600 atm according to ideal gas law?

9.     Define Graham's law of diffusion.

10. Give the values of R-gas constant in calories and Joules.

11. What are the units of Vanderwaals constants 'a' and 'b' ?

12. Write the significance of Vanderwaal's constants.

13. Write the limitations of vanderwaal equation of state.

14. Define Joule-Thomson effect.

UNIT-II

1.    Liquid and Solid State

1.1. Properties of Liquids

As you have studied earlier in this unit that the properties of liquids arise from (i) The nature and (ii) The magnitude of intermolecular forces of attraction existing between their molecules. The important properties of liquids are

1. Vapour pressure 2. Surface tension 3. Viscosity 4. Refraction  

1.2. Surface tension, viscosity and their applications.

The existence of strong intermolecular forces of attraction in liquids gives rise to a property known as surface tension. The phenomenon of surface tension can be described as follows.

A molecule in the interior of a liquid is attracted equally in all directions by the molecules around it. A molecule in the surface of a liquid is attracted only sideways and towards the interior. The forces on the sides being counterbalanced, the surface is pulled only inward the liquid. These unbalanced attractive forces acting downward tend to draw the surface molecules into the body of the liquid and, therefore, tend to reduce the surface to minimum. The liquid then behaves as if it were under a strain or tension. It is this force which is called surface tension. It may be defined as “the force in dynes acting on the surface of the liquid at right angles to one centimetre length of the surface”. It is represented by a symbol ɣ (gama).

In CGS system the unit of surface tension is dynes per centimetre (dyne cm-1). In SI system, the unit is Newton per metre (Nm-1). Both these units are related as follows

Effect of temperature on surface tension

When temperature increases, there is increase in kinetic energy of liquid molecules (KE α T) thereby decreasing intermolecular forces. It results in decrease in inward pull functioning on the surface of the liquid. That means you can say surface tension decreases with increase in temperature. As surface tension arises of the attractional forces operating between the molecules, Ramsay and Shields gave the following relationship between the surface tension of a liquid and its temperature.

γ (M/d)2/3 = k(tc-t-6)

where k is constant tc is critical temperature and t any other temperature γ (M/d)2/3 represents molar surface energy of liquid.

Viscosity

Some liquids flow more rapidly than others. In other words, liquid molecules pose resistance to the flow of one layer over the other. This property of liquids which determines their flow is termed viscosity. The property of the liquid which determines its flow is called viscosity of the liquid.

The resistance to flow of one layer of liquid molecules over another depends on the following factors.

1. The intermolecular attractive forces do not permit a free flow of molecules in a liquid. The strength of intermolecular forces gives a rough major of the viscosity of the liquids.

2. The molecular weight or mass of the molecules of a liquid also determines flow of the liquid. Thus heavier the molecule of a given liquid the greater will be its viscosity.

3. Structure and shape of the molecules of a liquid place an important role in influencing its viscosity. Liquids with the large irregularly shaped molecules are generally known to be more viscous than those with small and symmetrical molecule. Since only hard symmetrical molecules have perfectly elastic collision, the large and irregular molecules will have less elastic molecules amongst themselves. Thus collisions between large molecules involves the loss of kinetic energy and as a consequence the intermolecular forces dominating the molecules tends to stick together. This increases the viscosity of the liquid.

4. An increase in temperature decreases the viscosity of the liquid, the molecular motion increases at the expense of cohesive forces causing resistance to flow.

5. The increase of pressure goes to strengthen the cohesive forces between molecules.

Hence with increase of pressure the viscosity of a given liquid increases somewhat.

The flow is a characteristic property of liquids. Let us consider flow of a liquid. A liquid may be considered to be consisting of molecular layers arranged one over the other. When shearing force is applied, it flows.

However, the force of friction between the layers offers resistance to this flow. Viscosity of a liquid is a measure of its frictional resistance.

Let us examine a liquid flowing on a glass surface. The molecular layer in contact with the stationary surface has zero velocity. The successive layers above it move with increasingly higher velocities in the direction of the flow.

Now consider two adjacent moving layers of a liquid. Let these be separated by a distance dx having velocity difference d . The force of friction (F) resisting the relative motion of the two layers is directly proportional to the area A and velocity difference d , while it is inversely proportional to the distance between the layers dx.

where           η (eta) is the proportionality constant. It is known as coefficient of viscosity or simply viscosity of a liquid. It may be defined by the above equation as:

the force of resistance per unit area which will maintain unit different of velocity between two layers which are unit distance apart.

Unit of viscosity:

n = F/A x dυ/dx

= force/area x distance/velocity

= mass x length x time-2/length2 X length/length/time

= mass x length-1 x time-1

In CGS system the unit of 1'1 is expressed as g cm-1s-1, it is called poise. In practice smaller units centipoise (10-2 poise) and millipoise (10-3 poise) are used.

A liquid is said to have coefficient of viscosity as one poise when a force of one dyne maintains a velocity difference of one centimetre per second between two parallel layers of the liquid one cm apart and have an area of contact equal to on square cm. The reciprocal of viscosity is known as fluidity.

Effect of temperature on viscosity

As the temperature increases, the molecular motion increases at the expense of cohesive forces causing resistance to flow. Therefore, the viscosity of liquids is found to decrease by 1 to 2 per cent for each degree rise of temperature.

Determination of viscosity

The apparatus used for determination of viscosity in the laboratory is knwon as Ostwald’s viscometer. A simple form of Ostwald viscometer, the left- hand limb is essentially a pipette with two celibration marks A and B.  A length of capillary tube joins the pipette to the bulb D in the right-hand limb.

A definite volume of liquid (say about 25 ml) is poured into the bulb D with a pipette. The liquid is sucked up near to the top of the left-hand limb with the help of rubber tubing attached to it. The liquid is then released to flow back into the bulb D. the time t1 to flow from A to B is noted with a stopwatch. Then the apparatus is cleaned and the experiment is repeated with water taking about the same volume. The time of flow of water t2 from A to B is recorded. The density of the liquid d and that of water dw are determined with the help of density bottle. The relative viscosity is calculated from the expression

η/ηw = dt1/dwt2

where is η is coefficient of viscosity of the experimental liquid and ηw is the coefficient of viscosity of water. Knowing the value of coefficient of viscosity of water ηw at the temperature of experiment, the absolute viscosity coefficient η of the given liquid can be found.

Viscosity and chemical constitution As you know viscosity is largly due to intermolecular attractions which resist the flow of liquid. Therefore, some sort of relationship between viscosity and molecular structure should be there. Viscosity is also dependent on the shape, size and mass of the liquid molecules. The following general rules have been discovered.

(i) Dunstan Rule: Dunstan in 1909 showed that coefficient of viscosity η and molecular volume (d/M) were related as   d/M x ηx106 = 40 to 60 This expression holds only for normal (unassociated) liquids for associated liquids the value is much higher than 60. For example, the value for benzene is 73 and for water it is 559 and for ethanol it is 189. This shows benzene is a normal liquid while water and ethanol are associated liquids.

(ii) Molar Viscosity: The product of molar surface and viscosity is termed as molar viscosity. That is molar viscosity = molar surface x viscosity = (M/d)2/3 x ή Thorpe and Rodger (1894) found that molar viscosity is an additive property at the boiling point. They worked out the molar viscosity contributions of several atoms (C, H, O, S, etc) and groups. From these, they calculated the molar viscosity of liquid from its proposed structure. By tallying this value with the experimental one, they were able to ascertain the structure.

(iii) Rheochor: Newton Friend (1943) showed that if molecular volume (M/d) be multiplied by the eighth root of the coefficient of viscosity it gives a constant value [R], it is termed as Rheochor M/d x η1/8 = R Like parachor, rheochor is both additive and constitutive property.

1.3. Crystalline and amorphous

Solids can generally be classified into two broad categories:

(i) Crystalline solids (ii) Amorphous solids A crystalline solid exists as small crystals, each crystal having a characteristic geometrical shape. In a crystal, the atoms, molecules or ions are arranged in a regular, repeating three-dimensionl pattern called the crystal lattice. examples are sugar, salt etc.

An amorphous solid has atoms, molecules or ions arranged at random and lacks the ordered crystalline lattice. Examples of amorphous solids are rubber, plastics and glass.

In their disordered structure, amorphous solids are regarded as supercooled liquids with high viscosity. The liquid nature of glass is sometimes apparent in very old window panes that have become slightly thicker at the bottom due to gradual downward flow.

1.4.              Differences - geometry, isotropy and anisotropy, melting point;

Anisotropy and isotropy: Amorphous substances differ from crystalline solids and resemble liquids in another important aspect. Their properties such as electrical conductivity, thermal conductivity mechanical strength and refractive index are same in all directions.

Amorphous substances are said to isotropic. Liquids and gases are also isotropic.

Crystalline solids on the other hand are anisotropic, because their physical properties are different in different directions. For example the velocity of light through a crystal varies with the direction in which it is measured. Thus, a ray of light enter such a crystal may split up into two components each following different velocity. This phenomenon is known as double refraction.

Anisotropy in crystals is due to different arrangement of particles in different directions only two different kinds of atoms is depicted if the properties are measured along the direction indicated by the slanting line CD, they will be different from those measured in the direction indicated by the vertical line AB. The reason is that while in the first case, each row is made up of alternate types of atoms, in the second case; each row is made up of one type of atoms only. In amorphous solids, atoms or molecules are arranged at random and in a disorderly manner and, therefore all directions are identical and all properties are alike in all directions.

1.5. isomorphism, polymorphism.

In our surroundings, we can find numerous types of compounds, which are different in their appearances, or we can say that their morphologies differ. Some chemical properties are determined just by appearances. The morphology of a compound describes its external structure. The expressions isomorphism and polymorphism are utilised to describe the external features of compounds. The major difference between the two is that in isomorphism, two or more compounds show identical morphologies, whereas in the case of polymorphism, the same compound shows different morphologies.

  • Introduction to Isomorphism

The law of isomorphism was first given by Mitscherlich in 1819. When identical morphology is found in two or more compounds, they are called isomorphous compounds. This implies that crystal structure is present in not only a single compound but may be present in other compounds as well. This property is called isomorphism. 

  • Properties of Isomorphic Substances

The ratio of atoms found in isomorphic compounds is the same, which indicates the same empirical formula but the compounds differ in accordance with their atomic structure; therefore, they possess different physical properties. The different physical properties include density, mass, chemical reactivity, etc.

Conditions of Isomorphism

Polar organic compound:

  • Chemical formulas must be comparable.
  • There should be the same chemical and geometrical arrangement of ions in unit cells.
  • The size of the ions must not vary as much.
  • The polarisation of ions should be the same.

 Non-polar organic compound:

  • Molecular volume does not contain major differences.
  • The similarity in the crystal structure.
  • Similar chemical constituents are used.

Examples

The following examples show isomorphic nature:

  • Calcium carbonate and sodium nitrate

The shape of both the compounds is trigonal. The atomic ratio of all the elements present in them is 1:1:2. But it should be noted that the physical properties, chemical properties, and molar mass are different in both compounds.

  • Another example is potassium chromate and potassium sulphate.

Applications of Isomorphism

It is used for the following purposes:

  • Determination of atomic weight
  • Identifying the valency
  • Correction of atomic weight

Limitations of isomorphism

  • Isomorphism is shown by some of the compounds having differences in accordance with their crystalline structure. Examples of such compounds are ferrous sulphate and zinc sulphate.
  • It is mandatory for isomorphous substances that different structures of compounds have an equal number of ions in their unit cell. However, some of the compounds still do not obey this rule, yet they are isomorphous compounds.
  • Compounds with similar chemical formulas and the same number of atoms disobey the isomorphism condition and are non-isomorphous compounds.

Introduction to Polymorphism

When the same compound shows different morphologies, it is termed as polymorphism, and that particular substance is called a polymorphic substance. The shape and structure may differ for the same compound.

  • Properties of Polymorphic Substances

There is a difference in the physical and chemical properties of polymorphic substances. The physical properties like melting point, density, hardness, solubility, electrical conductivity differ in various polymorphic substances. The chemical reactivity of a substance also changes in different polymorphic substances. 

  • Factors Affecting Polymorphism
  • The polymorphism is affected by temperature and humidity. For example, solid ice melts down to liquid with an increase in temperature.
  • The polymorphism is affected by photostability. On exposure to visible light, the chemical and physical properties of a substance change.
  • The polymorphism is also affected by grinding. On grinding, the bond between the atom gets weaker. That is the reason why the anhydrous form is less stable than the dihydrate form.

Types of Polymorphism

  • Monotropic polymorph: Monotropic polymorph means that the compound exhibits several polymorphic forms, but out of them, only one form shows stability at all temperatures. Examples: Glyceryl stearate, Chloramphenicol palmitate, Metolazone.
  • Enantiotropic polymorph: At a certain temperature and pressure, one polymorph is stable, while others are stable at different ranges of pressure and temperature. Example: Sulphur 

Examples

  • Carbon has two polymorphs, which are graphite and diamond.
  • Calcium carbonate has two polymorphs, one is orthorhombic aragonite, and the other is hexagonal calcite.
  • Silicon oxides have six polymorphs.

Application of Polymorphism

Polymorphism has a wide range of applications in the pharmaceutical industries for the production of various kinds of drugs and medicines. It depends upon the chemical properties of the polymorphic forms. Since different polymorphic forms show different chemical properties, the effectiveness of drugs on the body can be determined accordngly.

Differences in Isomorphism and Polymorphism

                  Isomorphism

                      Polymorphism

Two or more compounds having the same morphologies are referred to as isomorphous substances.

Different morphologies are depicted by the same compounds.

Identical shapes

Different shapes

There must be two or more different compounds required.

There are different forms present for the same compound.

They have the same atomic ratio which is depicted by empirical formulas.

The polymorphic compounds may show similar or different atomic ratios.

 

1.6. Crystals –size and shape;

Crystals are bound by surface which is usually planner. These surfaces are called faces and where two faces intersect an edge is formed. The angle between the normals to the two intersecting faces is the interfacial angle or the angle between any two faces is called interfacial angle. Although the size of the faces or even shapes of crystals of one and the same substances may vary widely with the condition of formation or other factors, yet the interfacial angles between any two corresponding faces of the crystal remain invariably the same throughout. Now it is clear to you that although the external shape is different yet the interfacial angles are the same.

Space lattice

Rather than drawing the entire pattern, it is much more convenient to represent the unit of pattern by a point. Each point then represents the position of an atom, ion, molecule or group of ions and molecules. The regular three-dimensional arrangement of identical points in space gives rise to what is known as space lattice or crystal lattice (Fig 5.3) the positions occupied by the particles in the space lattice are called lattice sites or lattice points.

Unit cell:

It is defined as “the smallest geometrical portion of the crystal, which when repeated in three dimensional, would generate the complete crystal”. Each unit cell, in turn, must be constituted of atoms, molecules or ions, as the case may be and arranged to give the particular geometrical configuration of the crystal.

Unit cells are of following types;

(a) Simple or primitive unit cell (P): The simplest unit cell which has the lattice points at the corners is called a simple or primitive unit cell. It is denoted by P.

(b) Non primitive or multiple unit cell:  When unit cell contains more than one lattice points, it is called non primitive or multiple unit cell. It is further divided into the following three categories:

(i) Face centred unit cell (F): When a unit cell, besides the points present at the corners of the unit cell,

There is one point at the centre of each face, it is called face centred arrangement or face centred unit cell. It is denoted by F.

(ii)  Body centred unit cell (I): When in a unit cell, besides the points at the corners of the cell, there is one point at the centre with in its body, it is called body-centred arrangement or body-centred with cell. It is denoted by I.

(iii) Side centre or end face unit cell: When in a unit cell, besides the points at the corners of the cell, the points are located at the centre of any two parallel faces of the unit cell, it is called side-centred or end face unit cell. It is denoted by c.

1.7. laws of crystallography;

There are three laws of crystallography which deal with the interfacial angles and the rational indices.

Law of constancy of interfacial angle

The crystal may be smaller or bigger in size and may be prepared by any method, but the interfacial angles are always the same.

Law of rational indices

Now it will be clear to you that crystal lattice consists of unit cells arranged in parallel planes. Thus each crystal plane lies parallel to the crystal face as also to the unit cell face. These planes cut the three axes along the three crystallographic axes (ox, oy, oz), Hauy proposed that a given crystal plane could be described in terms of intercepts along the axes. The reciprocals of these intercepts are small whole numbers, these numbers h,k and l are called Miller indices after the name of British Scientist W.H. Miller. Thus Miller indices of a plane may be defined as the reciprocals of the intercepts which the plane makes will the axes.

For example let us consider a crystal system with the axes OX, OY and OZ. ABC represents a unit cell surface while LMN depicts another crystal plane under study

The intercepts of the unit plane are OA, OB and OC which have the length a,b and c respectively. The intercepts of the plane under study are OL, OM and ON. These can be expressed as multiples of the intercepts a,b,c i.e. la, mb and nc. Here l m and n are either integral whole numbers or fraction of whole numbers. The reciprocal of these numbers are written together in brackets (h,k.l) to give the Miller indices of the plane under study.

To find the Miller indices proceed as follows.

(i) Write the intercepts as multiples of a,b,c say la, mb, nc

(ii) Take the reciprocals of l, m and n

(iii)Clear fraction to get whole numbers h,k,l. (iv) Miller indices to the plane are (h,k,l).

Example:  calculate the Miller indices of crystal planes which cut through the crystal axes at

1.8. symmetry elements – plane, centre and axis; Miller indices

Law of symmetry

Besides the interfacial angles, another important property of crystals is their symmetry. The law of symmetry states that: All crystals of the same substance possess the same elements of symmetry.

Symmetry in crystals may be with respect to a plane, a line or a point, accordingly there are three types of symmetry associated with a crystal.

Plane of symmetry When an imaginary plane can have divided a crystal into two parts such that one is the exact mirror image of the other, the crystal is said to have a plane of symmetry.

Axis of symmetry An axis of symmetry is a line about which the crystal is rotated such that it presents the similar appearance more than once during complete rotation i.e. rotation through an angle of 3600. Depending upon its nature, a crystal may have 2-fold, 3-fold, 4-fold or 6-fold axes of rotation.

For example in the case of a cube, an axis passing perpendicularly through the centre is such that when the cube is rotated it presents similar appearance in three rotation of 900 each and the same appearance after the fourth rotation, such an axis is called a four-fold or tetrad axis. If the same similar appearance is repeated after an angle of 1800, the axis is called two-fold or diad axis. In the same way, if the same or similar appearance is repeated after an angle of 1200, the axis is called a three-fold or triad axis . If the same or similar axis is repeated after an angle of 600, as in the case of a hexagonal crystal, the axis is called six-fold or hexad axis. In general, if the same or similar appearance of a crystal is repeated on rotation through an angle of 360/n, around an imaginary axis, the axis is called an n- fold axis.

100, 110 and 111 planes of a crystal

100 plane , 110 plane  ,     111 planes

Centre of Symmetry

It is a pound at the centre of the crystal so that any line drawn through it will meet the surface of the crystal at equal distance on either side.

It may be pointed out that a crystal may have number of planes or axis of symmetry but it has only one centre of symmetry.

1.9. Unit cells and space lattices

Crystalline solid is characterised by a definite orientation of atoms, ions or molecules, relative to one another in a three dimensional pattern. The regular arrangement of these species throughout the crystal is called a crystal lattice. A basic repeating structural unit of a crystalline solid is called a unit cell. The following figure illustrates the lattice point and the unit cell.

A crystal may be considered to consist of large number of unit cells, each one in direct contact with its nearer neighbour and all similarly oriented in space. The number of nearest neighbours that surrounding a particle in a crystal is called the coordination number of that particle.

A unit cell is characterised by the three edge lengths or lattice constants a, b and c and the angle between the edges α, β and ɣ.

1.10.            classification of crystal systems

There are seven primitive crystal systems; cubic, tetragonal, orthorhombic, hexagonal, monoclinic, triclinic and rhombohedral. They differ in the arrangement of their crystallographic axes and angles. Corresponding to the above seven, Bravais defined 14 possible crystal systems as shown in the figure.

1.11.             Bravais lattices

1.12.            X – ray diffraction  

You know that when x-rays were first investigated, problem arose of measuring their wave length. It is a well known fact that, if light is allowed to strike a surface consisting either of a series of edges or lines spaced closely enough to be of the same order of magnitudes as that of the wavelength of light, the beam of light is diffracted. And the various radiations are dispersed into a series of spectra known as, first, second, third etc. order of spectra. Further, there is definite relation between the angle of diffraction, the wavelength of radiation and the spacing of the lines on the ruled grating. Since x-rays are of the same nature as light, it should be theoretically possible to determine the wavelength of this radiation in the same way. However, it is impossible by any mechanical means to rule a grating as fine as that required, namely one with 108 lines per centimeter. For this purpose, Laue (1912) suggested that crystal can act as grating to x-rays as wavelength of x-rays is comparable to the interatomic distance. When a beam of x-rays is allowed to fall on a crystal, a large number of images of different intensities are formed. If the diffracted waves are in the same phase, they reinforce each other and a series of bright spots are produced on a photographic plate placed in their path. On the other hand, if the diffracted waves are out of phase, dark spots are caused on the photographic plate. From the overall diffraction pattern produced by a crystal, can arrive at the detailed information regarding the position of particles in the crystal.

1.13.            Bragg’s equation

Bragg’s pointed that the scattering of x-rays by crystal could be taken to be equivalent to reflection from successive planes of atoms in the crystal. However, the reflection of x-rays can take place only at certain angles which are dependent on wavelength of the x-rays and the distance between the planes of the crystal. The fundamental equation which gives a simple relation between the wave length of x-rays, the interplaner distance in the crystal and the angle of reflection is known is known as Bragg’s equation. This equation can be derided as follows.

The horizontal lines represent parallel planes in the crystal structure separated from one another by a distance d. suppose a beam of x-rays incident at an angle falls on the crystal. Some of them will be reflected from uppermost plane at the same angle, while the other will be absorbed and get reflected from successive planes, as shown in

X-Ray diffraction analysis is the most powerful tool for the determination of crystal structure. The inter planar distance (d) between two successive planes of atoms can be calculated using the following equation form the X-Ray diffraction data

2dsinθ = nλ

The above equation is known as Bragg’s equation.

Where λ is the wavelength of X-ray used for diffraction. θ  is the angle of diffraction n is the order of diffraction By knowing the values of θ,λ and n we can calculate the value of d.

d = nλ / 2sinθ

Using these values, the edge length of the unit cell can be calculated.

Packing in atomic solids

1.14.           simple cubic

In the simple cubic unit cell, each corner is occupied by an identical atoms or ions or molecules. And they touch along the edges of the cube, do not touch diagonally. The coordination number of each atom is 6. Each atom in the corner of the cubic unit cell is shared by 8 neighboring unit cells and therefore atoms `per unit cell is equal to NC /8 where Nc is the number of atoms at the corners.

Number of atoms in a SC unit cell

1.15.            body centered cubic

In a body centered cubic unit cell, each corner is occupied by an identical particle and in addition to that one atom occupies the body centre. Those atoms which occupy the corners do not touch each other, however they all touch the one that occupies the body centre. Hence, each atom is surrounded by eight nearest neighbours and coordination number is 8. An atom presents at the body centrebelongs to only to a particular unit cell i.e unshared by other unit cell.

Number of atoms in a bcc unit cell

   

1.16.            face centered cubic

In a face centered cubic unit cell, identical atoms lie at each corner as well as in the centre of each face. Those atoms in the corners touch those in the faces but not each other. The atoms in the face centre is being shared by two unit cells, each atom in the face centers makes 1/2 contribution to the unit cell.

Number of atoms in a fcc unit cell      

   

1.17.            hexagonal close packing

Crystalline solids exhibit a regular and repeating pattern of constituent particles. The diagrammatic representation of three-dimensional arrangements of constituent particles in a crystal, in which each particle is depicted as a point in space is known as a crystal lattice. In a crystal lattice, the atoms are very closely packed, leaving very little space between them. This arrangement of elements in solids also helps us in the determination of the formula of a compound. We have learned three-dimensional solid packing can be packed in two ways viz., cubical close packing (CCP) and hexagonal close packing (HCP).

In hexagonal close packing (HCP) too, there are two basic kinds of voids are involved, namely, octahedral voids and tetrahedral voids. We know that the number of tetrahedral voids present in a lattice is twice the number of close-packed particles. While the number of octahedral voids generated is equal to the number of close-packed particles. The arrangement of particles in these voids depends on other factors too. For example, in ionic solids, the bigger ions from the close-packed structure and the smaller ions occupy the voids. Tetrahedral voids are occupied if the latter ions are small. Whereas if the latter ions are bigger, octahedral voids are occupied. The fraction of octahedral or tetrahedral voids occupied by the molecules helps us in the determination of the formula of the compound.

Problems on hexagonal close packing Formula

Question: Atoms of element Y form hexagonal close packing lattice and those of the element X occupy 1/4th of tetrahedral voids. What is the formula of the compound formed by the elements X and Y?

Solution: The number of tetrahedral voids formed = 2 × (number of atoms of element Y)

Since only 1/4th of these voids are occupied by X, the ratio of elements of X to Y can be given by:

2 × (1/4):1 or 1:2

Thus, the formula of the compound is XY2.

 

1.18.            Co-ordination number in typical structures NaCl, CsCl, ZnS, TiO2

Structure of NaCl crystal

The ionic crystal of NaCl is shown in Figure. Each sodium ion is surrounding by six chloride ions and each chloride ions is surrounded by six sodium ions. The maximum intensity of reflection occurs at the glancing angle of 5.90, 8.40 and 5.20 for 100, 110 and 111 planes, respectively for first order reflection.

 

For face-centred cubic system the planes can be passed through the atom having Miller indices 100, 110 and 111 at the relative spacing a/2:a/2 2: a/ 3

So d100:d110:d111 = a/2:a/2 2:a/ 3

= 1:0.707:1.154

This ratio is almost identical with the ratio we have calculated from experimental observations. Hence NaCl crystal is face-centred cubic system.

 

Structure of CsCl crystal

Cesium chloride, CsCl, has a body centred cubic structure. In its crystal lattice, each

Cs+ ion is surrounded by 8 Cl- ions and its coordination number is 8. The value of distance between Cs+ ion and Cl- ion as determined by Bragg’s spectrometer is 3.5100A

1.19.            comparison of structure and properties of diamond and graphite

The diamond lattice consists of a series of atoms, each of which is placed between four neighbours. The latter occupies the angular points of a regular tetrahedral, while atom under consideration lies in the centre. The type of structure runs throughout the crystal. The C-C bond distance is 0.154 nm. The whole lattice is continuous. The diamond crystal is regarded as giant molecule. The crystal is very hard because the covalent links runs without a break throughout the whole crystal. The crystal can be cut only by breaking the covalent links. High melting point can also be explained by stating that the atoms are very firmly attached within the crystal.

Though diamond and graphite are both covalent crystals. The great difference between graphite and diamond can be understood in terms of the crystal lattice. Graphite has hexagonal networks in sheets like benzene rings. The distance between atoms in the plain is 142 pm but the distance between these atomic layer planes is 335 pm. In two directions the carbon atoms are tightly held as in diamond, but in the third direction, the force of attractions appreciably less. As a result one layer can slip over the other. The crystal is flatty.

DIAMOND

GRAPHITE

Diamonds have a strong three-dimensional network structure

Graphites have a two-dimensional sheet-like structure

The networks are formed because of the presence of covalent bonds.

They are formed due to weak Van der Waal's forces of attraction.

They are hard in nature.

They are soft in nature.

Molecules are closely packed, as a result, they have high density.

There is a large gap between molecules. Therefore, they have low density.

There is no presence of free carbon atoms in diamonds.

There is presence of free Carbon atoms in graphite.

Diamonds do not conduct electricity.

Graphite conducts electricity.

 

1.20.           numerical problems involving core concepts

Q.2 Metallic gold Au=197 is face centred cubic lattice. Calculate (a) how many atoms occupy the gold unit cell and (b) what is the mass number of a gold unit cells.

Solution:

1.21.            Defects in solids –

According to the law of nature nothing is perfect, and so crystals need not be perfect.  They always found to have some defects in the arrangement of their constituent particles. These defects affect the physical and chemical properties of the solid and also play an important role in various processes. For example, a process called doping leads to a crystal imperfection and it increases the electrical conductivity of a semiconductor material such as silicon. The ability of ferromagnetic material such as iron, nickel etc., to be magnetized and demagnetized depends on the presence of imperfections. Crystal defects are classified as follows

1) Point defects

2) Line defects

3) Interstitial defects

4) Volume defects

In this portion, we concentrate on point defects, more specifically in ionic solids.

Point defects are further classified as follows

1.22.           stoichiometric defects.

This defect is also called intrinsic (or) thermodynamic defect. In stoichiometric ionic crystals, a vacancy of one ion must always be associated with either by the absence of another oppositely charged ion (or) the presence of same charged ion in the interstitial position so as to maintain the electrical neutrality.

Schottky defect:

Schottky defect arises due to the missing of equal number of cations and anions from the crystal lattice. This effect does not change the stoichiometry of the crystal. Ionic solids in which the cation and anion are of almost of similar size show Schottky defect. Example: NaCl.Presence of large number of Schottky defects in a crystal, lowers

its density. For example, the theoretical density of vanadium monoxide (VO) calculated using the edge length of the unit cell is 6.5 g cm-3, but the actual experimental density is 5.6 g cm-3. It indicates that there is approximately 14% Schottky defect in VO crystal.

Presence of Schottky defect in the crystal provides a simple way by which atoms or ions can move within the crystal lattice.

Frenkel defect:

Frenkel defect arises due to the dislocation of ions from its crystal lattice. The ion which is missing from the lattice point occupies an interstitial position. This defect is shown by ionic solids in which cation and anion differ in size. Unlike Schottky defect, this defect does not affect the density of the crystal.

For example, AgBr, in this case, small Ag+ ion leaves its normal site and occupies an interstitial position as shown in the figure.

1.23.           Non-stoichiometric defects.

Non-stoichiometric compounds are those compounds in which proportion of cation and anion is not similar and defects of these compounds are known as non-stoichiometric defects. In this defect a large number of positive and negative charges are present. As we know, crystals remain neutral so, if a spare amount of negative charge is present then it will be maintained by extra positive charge presence. Because of this positive and negative charge, solid crystal structure shapes will become improper, and solid become imperfect.

This defect can be happened due to 2 reasons:

In a lattice, substances have a cation whose proportion is more than in an anion. Hence, known as a metal excess defect.

In a lattice, substances have a cation whose proportion is lesser than in an anion. And hence known as the metal deficiency defect.

Metal excess defect:

Metal excess defect arises due to the presence of more number of metal ions as compared to anions.

Alkali metal halides NaCl, KCl show this type of defect.

The electrical neutrality of the crystal can be maintained by the presence of anionic vacancies equal to the excess metal ions (or) by the presence of extra cation and electron present in interstitial position.

For example, when NaCl crystals are heated in the presence of sodium vapour, Na+ ions are formed and are deposited on the surface of the crystal. Chloride ions (Cl-) diffuse to the surface from the lattice point and combines with Na+ ion. The electron lost by the sodium vapour diffuse into the crystal lattice and occupies the vacancy created by the Cl- ions. Such anionic vacancies which are occupied by unpaired electrons are called F centers. Hence, the formula of NaCl which contains excess Na+ ions can be written as Na1+x Cl.

ZnO is colourless at room temperature. When it is heated, it becomes yellow in colour.

On heating, it loses oxygen and thereby forming free Zn2+ ions. The excess Zn2+ ions move to interstitial sites and the electrons also occupy the interstitial positions.

Metal deficiency defect:

Metal deficiency defect arises due to the presence of less number of cations than the anions. This defect is observed in a crystal in which, the cations have variable oxidation states.

For example, in FeO crystal, some of the Fe2+ ions are missing from the crystal lattice.

To maintain the electrical neutrality, twice the number of other Fe2+ ions in the crystal is oxidized to Fe3+ ions. In such cases, overall number of Fe2+ and Fe3+ ions is less than the O2- ions. It was experimentally found that the general formula of ferrous oxide is FexO, where x ranges from 0.93 to 0.98.

Impurity defect:

A general method of introducing defects in ionic solids is by adding impurity ions. If the impurity ions are in different valance state from that of host, vacancies are created in the crystal lattice of the host. For example, addition of CdCl2 to AgCl yields solid solutions where the divalent cation Cd2+ occupies the position of Ag+. This will disturb the electrical neutrality of the crystal. In order to maintain the same, proportional number of Ag+ ions leaves the lattice. This produces a cation vacancy in the lattice, such kind of crystal defects are called impurity defects.

1.24.           Liquid crystals

There are certain solids which on heating undergo two sharp phase changes one after the other. They first fuse sharply yielding turbid liquids and again equally sharply at higher temperature yielding clear liquids. These changes get reversed on cooling at the same temperature. The turbid liquid show anisotropy i.e. they have different physical properties from different directions. Anisotropy is particularly seen in the optical behaviour of liquids. In an anisotropic substance, the physical property are different in different direction. On the other hand true liquids are isotropic ie same physical properties in different directions. As anisotropic properties are associated with crystalline state, the turbid liquids are known as liquid crystals.

This liquid crystal term, however, is not satisfactory since the substances in this state do not have properties of crystalline state. Actually, they are more like liquids in having properties like mobility, surface tension, viscosity etc. Amongst other names that have been suggested are crystalline liquids and anisotropic liquids, but these are also not satisfactory. The term mesomorphic state (meaning intermediate form) probably fits best. But, the older term liquid crystal continues to be used even in the present day literature.

Substances which show the above behaviour are usually some long chain organic molecules either terminating in groups such as-OR, -COOR or having groups like -C=N-,-N=NO-,-C=C- in the middle. The first solid showing this peculiar property was discovered in 1888 was cholesteryl benzoate C6H5COOC27H45. It fuses sharply at 1450C to form turbid liquid and on further heating changes into clear liquid at 1780C. If we cool, the above changes are reversed i.e., the clear liquid when cooled first changes into turbid state at 1780C and then into the solid state at 1450C

Later on, p-azoxyanisole and p-azoxyphenetone were found to exhibit the same properties. In 1991 P.G. De Genees, a French physicist got the Nobel Prize in Physics for contribution to liquid crystals and polymers.

1.25.           classification and applications.

In a liquid the moleucules have random arrangement and they are able to move fast each other. In a solid crystal the molecules have an ordered arrangement and are in fixed positions. In a liquid crystal, however, molecules are arranged parallel to each other and can flow like a liquid. Thus liquid crystals have the fluidity of a liquid and optical properties of solid crystals. Accordingly, to their molecular arrangement, the liquid crystals are classified into three types

Nematic liquid crystals:

in nematic liquid crystals molecules are parallel to each other like soda straws but they are free to slide or roll individually.

Smetic liquid crystals:

The molecules in this type of liquid crystals are also parallel but these are arranged in layers. These layers can slide past each other.

Cholesteric liquid crystals:

As in nematic crystals in this type liquid crystals the molecules are parallel but arranged in layers. The molecules in successive layers are slightly rotated with respect to the layers above and below so as to form spiral structure.

Application of liquid crystals:

On account of their remarkable optical and electrical properties, liquid crystal found several practical applications. Some of these are given below.

Number display:

When a thin layer of nematic liquid crystal is placed between two electrodes and an electrical field is applied, the polar molecules are pulled out of alignment. This cause the crystal to be opaque. Transparency returns when electrical signal is removed. This property is used in the number displays of digital watches, calculators, and other instruments.

Monitoring body temperature:

Like the solid crystals, liquid crystals can diffract light. Only one of the wavelengths of the white light is refracted by the crystal which appears coloured. As the temperature changes the distance between the layers of molecules also changes. Therefore, the colours of the reflected light changes correspondingly. These colesteric liquid crystal undergoes a series of colour changes with temperature. These crystals are used in indicator tapes to monitor body temperature or to spot areas of overheating in mechanical systems.

Uses of Liquid Crystals

Because liquid crystals have unusual physical and optical properties, they are used in many ways. As proof –

(i) Color of cholesteryl crystals depends on temperature. Therefore, to calculate the temperature, the temperature calculation helps a lot.

(ii) Used in gas-liquid colorimetric analysis.

(iii) As they consume very little power, they are used in many electronic devices (calculator, clock, digital display).

(iv) Used as solvents in programmatic studies to investigate the design of molecules with vectorial properties.

(v) Cholesterol crystals can be used to detect and detect lesions in the body.

Vitreous State

Boron trioxide, silicon dioxide, germanium dioxide, etc., do not give solid crystals when cooled suddenly in the molten state of athene. Instead, they give a glassy substance. This state is Vitreous State.

Objects that give a mirror state

(i) Boron trioxide

(ii) Silicon dioxide

(iii) Germanium dioxide (iv) Arsenic oxide

(v) Phosphorus pentoxide

(vi) Beryllium fluoride

(vii) Glycerol

(viii) Glucose

When examining the properties of objects in the glassy state

They have been found to have both solid and liquid properties. As evidence

(A) Solid state properties

(i) High rigidity (ii) Inflexible

(iii) Bearing all forces.

(B) Liquid phase properties

(i) Light penetration takes place

ii) have similar optical properties in all directions.

Therefore, the glassy state can be considered as an intermediate state between the solid state and the liquid state.

Unlike perfect solid crystals, glassy materials do not melt at a certain temperature. Therefore, molecules and their structure in glassy materials can be considered to be disordered. Therefore, glassy materials can be considered non-crystalline, fine powders. When glassy materials are left alone at high temperatures for long periods of time, crystals emerge from them. Then, the mirror state disappears. Therefore, glassy materials can be considered as either amorphous solids or supercooled liquids.

Short Answer Questions:

1.     Define surface tension. What is its unit?

2.     How does vapour pressure varies with temperature.

3.     Explain why

(i)     Drops of liquids are spherical in shape.

(ii)   At the boiling point, the temperature of liquid does not rise although it is being heated.

(iii) Glycerol is more viscous than water.

4.     Write a note on specific refraction.

5.     Write a note on liquid crystals.

6.     Explain the term viscosity of a liquid.

 

Long Answer Questions:

1.      Define the terms surface tension and surface energy. Discuss capillary rise method for determination of surface tension in the laboratory.

2.      What are liquid crystals? How are they classified? How would you account for turbidity observed in liquid crystals? What are the uses of liquid crystals?

3.      Why do you use the same viscometer for the liquid and water during the experimental determination of the viscosity of the liquid by Ostwald viscometer? Describe the experiment.

4.       Write notes on the following

·       Vapour pressure

·       Optical oxaltation

·       Ramsay- Shields equation


 

UNIT-III

2.   Nuclear Chemistry

2.1. Natural radioactivity - α, β and ɣ rays

Radioactivity : The phenomenon of spontaneous disintegration of certain atomic nuclei resulting in the emission of radioactive rays is called radioactivity. Radioactivity is a nuclear phenomenon and it is not affected by external factors such as temperature, pressure etc. This phenomenon was discovered by Henry Becqurel.

To explain the spontaneous decay of radioactive elements, Rutherford and Soddy put forward the theory of radioactive disintegration. According to this theory the quantity of a radioactive element which disappears in unit time is directly proportional to the amount (atoms) of radioactive substance present at that time.

Based on the above theory, the following equation is derived which confirms that all radioactive reactions follow I order

2.2.             Half-life period

The time required to disintegrate one half of any radioactive substance is called half life period (t1/2). The half life period (t1/2) of a radioactive substance is independent of initial concentration. It depends only on the disintegration constant (X) of the radioactive element. t/ is used to indicate the relative stability of radioactive substance. If t1/2 is the shorter, faster is the rate of decay and hence the substance is more unstable and viceversa.

Since radioactivity is a nuclear phenomenon, it must be connected with the instability of the nucleus.

An a - particle is equal to the bundle of two protons and two neutrons and hence it is equal to the Helium nucleus (2He4).

p-particle is a fast moving electron.

ɣ—radiation is a waver of very short wavelength with very high energy.

Radioactive decay series: Radioactive heavy nuclei decay by a series of α - emission or β emissions, finally resulting in the formation of a stable isotope of lead. There are about 4 decay series.

4n - Thorium series

4n+1 - Neptunium series

4n+2 - Uranium series

4n+3 - Actinium series

2.3.             Fajan–Soddy group displacement law

Soddy and Kasimir Fajans independently unraveled the pattern of transformations that accompanied α and β ra- dioactive decay. They gave a law, to know the position of new element formed after the emission of α & β-particle.

According to the Group displacement law...

• If an α-particle is emitted by a radio active element from its nucleus, the atomic no.(Z) of new element or daughter element formed is decreased by 2 units & the mass number (A) is decreased by 4 units. Therefore, the position of new element formed is displaced by two groups towards the left in the periodic table.

• If a β-particle is emitted by a radioactive element, the atomic number of daughter element or new element is increased by one unit. Therefore, the position of new element is displaced by one group towards the right in periodic table.

• If an α-particle is emitted from the nucleus of radioactive element and then 2β-particles are emitted in next two transformations, the daughter element is an isotope of parent element. The daughter & parent element has the same atomic number. Hence according to Group displacement law position of daughter & parent element in the periodic table will remain same.

• Group displacement law is not applicable to lanthanides & actinides. (ie for f-block elements).

2.4.             Geiger–Nattal rule

In Gamow’s theory of α-decay we have considered an alpha particle in a nucleus as a particle in a box. The particle is in a bound state because of the presence of the strong interaction potential. It will constantly bounce from one side to the other, and due to the possibility of quantum tunneling by the wave through the potential barrier, each time it bounces, there will be a small likelihood for it to escape. But once it comes out of the nucleus how far will it travel before getting detected. Or in a way where should we place our detector so that we can have an α-particle detection.

See in the Gamow’s theory the disintegration constant depends on the energy of the α-particle meaning it’s the energy content of α-particle because of which it will travel. Geiger and Nuttall made experimental study between the decay constant (λ) and the range of the α-particle (Rα) for different α-emitters. What they have found is the following.

For an α-emitting radioactive substance the logarithm of the decay constant (λ) and the logarithm of

Dr. Upakul Mahanta, Department of Physics, Bhattadev University

the range of the α-particle (Rα) in air are in linear relation to each other.

To put it in a mathematical way

where C1, C2 are constants. But the above expression is an empirical one. Then again they have also showed that the range of the α-particle (Rα) also depends upon the velocity of the α-particle in air and in fact they have found it is proportional to the cubed of the velocity of the α-particle.

v3 = kv3

k is proportionality constant. Again

which is the Geiger-Nuttall Law in terms of energy with the assumption that c1 3/2 = A and c1 B1 + c2 = B. Thus the GeigerNuttall law also relates the decay constant of a radioactive isotope with the energy of the a-particles emitted. And the thumb rule is that the short-lived nuclei emit more energetic alpha particles than long-lived ones.

 

 

2.5.             isotopes, isobars, isotones

Isotopes are variants of a particular element with different numbers of neutrons. For example, the two isotopes of Uranium are, 23592 U and 23992 U. You will see here that the number of protons is the same in both the isotopes, but they contain 143 and 147 neutrons, respectively. The presence of an extra neutron significantly changes the behaviour of that particular atom. There are two different types of isotopes, stable and radioactive. Stable isotopes can exist in their free state without breaking down spontaneously. Radioactive isotopes are too unstable to sustain themselves, and they spontaneously break down into two lighter daughter elements with the emission of particles such as alpha, beta, and gamma rays.

Isobars are elements that have the same number of nucleons (sum of protons and neutrons). The series of elements with 40 Mass numbers serve as a good example; 4016S, 4017Cl, 4018Ar, 4019K, and 4020Ca. The nucleus of all the above-mentioned elements contain the same number of particles in the nucleus but contain varying numbers of protons and neutrons.

Isotones are atoms that have the same neutron number but different proton number. For example, 3616S, 3717Cl, 3818Ar, 3919K, and 4020Ca are all isotones of 20 since they all contain 20 neutrons.

2.6.             Mirror nuclei

A mirror nucleus is defined as the nucleus that contains a number of protons and a number of neutrons that are mutually interchangeable when compared to another nucleus are called a mirror nucleus.

The mirror nucleus pairs have equal spins and the same parity.

If the number of protons of the first isotope is designated by (Z1) then the number of neutrons of the second isotope is designated as (N2) are equal.

Z1=N2

If the number of protons of the second isotope is designated by (Z2) then the number of neutrons of the first isotope is designated as (N1) are equal.

Z2=N1

The mass number of both nuclei are the same.

Z1+N1=N2+Z2

Examples:

(I)14𝐶 𝑎𝑛𝑑 14𝑂 are mirror nuclei

Isotope 1

Z1

N1

Isotope 2

Z2

N2

14𝐶

6

8

14𝑂

8

6

So, mass number of both the nucleus is equal.

Z1+N1=N2+Z2

6+8=8+6

(II) 15𝑁 𝑎𝑛𝑑 15𝑂 are mirror nuclei

Isotope 1

Z1

N1

Isotope 2

Z2

N2

15𝑁

7

8

15𝑂

8

7

So, the mass number of both the nucleus is equal.

Z1+N1=N2+Z2

7+8=8+7

2.7.              iso diaphers

Isodiaphers are defined by the number of protons and neutrons in an atom’s nucleus.

Any element with a specific number of protons and neutrons in its nucleus is called a nuclide. The number of neutrons in a nuclide may differ from the number of protons.

These nuclides are employed in nuclear reactions because their nuclei contain energy for the same reason. Isodiaphers are a pair of nuclides with the identical number of protons and neutrons in the atom’s nucleus.

Although the nuclei of both nuclides have different numbers of protons and neutrons, the difference between them is the same.

Take Uranium 92U238 and thorium 90Th234, for example.

 

Uranium’s nucleus contains 92 protons and 146 neutrons, hence the difference is:

146 – 92 = 54

Thorium’s nucleus contains 90 protons and 144 neutrons, hence the difference is:

144 – 90 = 54

As a result, isodiaphers are nuclei with the same amount of protons and neutrons in their nucleus.

Take Uranium 92U238 and thorium 90Th234, for example. They have the difference of 54.

The mass number of any element is equal to the sum of its protons and neutrons, but the atomic number of any element is equal to the number of protons in that atom plus the number of electrons. Nuclides carry out nuclear reactions such as fission and fusion, which divide or combine atoms to generate new ones, releasing a lot of energy.

2.8.             Nuclear isomerism

Nuclear isomerism is caused due to the two lowest nuclear states with zero angular momentum and the opposite party. Their lifetime is estimated under these conditions of two quanta and for the ejection of two elections from the K or L shell. It is also exhibited by all diatomic molecules having an odd Z value.

2.9.             radioactive decay series

The spontaneous change of an unstable nuclide into another is radioactive decay. The unstable nuclide is called the parent nuclide; the nuclide that results from the decay is known as the daughter nuclide. The daughter nuclide may be stable, or it may decay itself. The radiation produced during radioactive decay is such that the daughter nuclide lies closer to the band of stability than the parent nuclide.

Types of Radioactive Decay

Ernest Rutherford’s experiments involving the interaction of radiation with a magnetic or electric field helped him determine that one type of radiation consisted of positively charged and relatively massive αα particles; a second type was made up of negatively charged and much less massive β particles; and a third was uncharged electromagnetic waves, γ rays. We now know that αα particles are high-energy helium nuclei, β particles are high-energy electrons, and γ radiation compose high-energy electromagnetic radiation. We classify different types of radioactive decay by the radiation produced.

 

Alpha particles, which are attracted to the negative plate and deflected by a relatively small amount, must be positively charged and relatively massive. Beta particles, which are attracted to the positive plate and deflected a relatively large amount, must be negatively charged and relatively light. Gamma rays, which are unaffected by the electric field, must be uncharged. A diagram is shown. A gray box on the left side of the diagram labeled “Lead block” has a chamber hollowed out in the center in which a sample labeled “Radioactive substance” is placed. A blue beam is coming from the sample, out of the block, and passing through two horizontally placed plates that are labeled “Electrically charged plates.” The top plate is labeled with a positive sign while the bottom plate is labeled with a negative sign. The beam is shown to break into three beams as it passes in between the plates; in order from top to bottom, they are red, labeled “beta rays,” purple labeled “gamma rays” and green labeled “alpha rays.” The beams are shown to hit a vertical plate labeled “Photographic plate” on the far right side of the diagram.

Alpha (αα) decay is the emission of an α particle from the nucleus. For example, polonium-210 undergoes α decay:

84Po2102He4+82Pb206 or 84Po2102α4 + 82Pb206

Alpha decay occurs primarily in heavy nuclei (A > 200, Z > 83). Because the loss of an α particle gives a daughter nuclide with a mass number four units smaller and an atomic number two units smaller than those of the parent nuclide, the daughter nuclide has a larger n:p ratio than the parent nuclide. If the parent nuclide undergoing α decay lies below the band of stability, the daughter nuclide will lie closer to the band.

Beta (β) decay is the emission of an electron from a nucleus. Iodine-131 is an example of a nuclide that undergoes β decay:

53I131−1e0+ 54X131 or 53I131−1β0+54Xe131

Beta decay, which can be thought of as the conversion of a neutron into a proton and a β particle, is observed in nuclides with a large n:p ratio. The beta particle (electron) emitted is from the atomic nucleus and is not one of the electrons surrounding the nucleus. Such nuclei lie above the band of stability. Emission of an electron does not change the mass number of the nuclide but does increase the number of its protons and decrease the number of its neutrons. Consequently, the n:p ratio is decreased, and the daughter nuclide lies closer to the band of stability than did the parent nuclide.

Gamma emission (γ emission) is observed when a nuclide is formed in an excited state and then decays to its ground state with the emission of a γ ray, a quantum of high-energy electromagnetic radiation. The presence of a nucleus in an excited state is often indicated by an asterisk (*). Cobalt-60 emits γ radiation and is used in many applications including cancer treatment:

27Co600γ0+27Co60

There is no change in mass number or atomic number during the emission of a γ ray unless the γ emission accompanies one of the other modes of decay.

Positron emission (β+ decay) is the emission of a positron from the nucleus. Oxygen-15 is an example of a nuclide that undergoes positron emission:

8O15+1e0+7N15 or 8O15+1β0+7N15

Positron emission is observed for nuclides in which the n:p ratio is low. These nuclides lie below the band of stability. Positron decay is the conversion of a proton into a neutron with the emission of a positron. The n:p ratio increases, and the daughter nuclide lies closer to the band of stability than did the parent nuclide.

Electron capture occurs when one of the inner electrons in an atom is captured by the atom’s nucleus. For example, potassium-40 undergoes electron capture:

19K40+−1e018Ar40

Electron capture occurs when an inner shell electron combines with a proton and is converted into a neutron. The loss of an inner shell electron leaves a vacancy that will be filled by one of the outer electrons. As the outer electron drops into the vacancy, it will emit energy. In most cases, the energy emitted will be in the form of an X-ray. Like positron emission, electron capture occurs for “proton-rich” nuclei that lie below the band of stability. Electron capture has the same effect on the nucleus as does positron emission: The atomic number is decreased by one and the mass number does not change. This increases the n:p ratio, and the daughter nuclide lies closer to the band of stability than did the parent nuclide. Whether electron capture or positron emission occurs is difficult to predict. The choice is primarily due to kinetic factors, with the one requiring the smaller activation energy being the one more likely to occur.

2.10.           magic numbers

1.     Pairs of nucleons frequently form inside. A single unpaired nucleon can be taken out of the nucleus more easily than a paired one. Two protons and two neutrons combine to form a very stable nucleus. The fact that a particle has a significant binding energy of approximately 28.3 MeV lends support to this.

2.     The graph between binding energy per nucleon and atomic number exhibits numerous kinks, one of which is illustrated as an example in the range A= 126 to 150 in Fig. These kinks are associated with a sharp increase in the binding energy per nucleon.

These kinks or discontinuities have been found to occur whenever either the Neutron number or the proton number or both take the values 2,8,20,50,82 and 126. Nuclei containing 2,8,20,50,82 and 126 nucleons of the same kind known as Magic numbers, have a very high stability. For example, 2He4 with Z=N=2 and 8O16 with Z = N = 8 are highly stable. Similarly, the nuclei with 14,28 and 40 nucleons (semi-magic numbers) are slightly less stable but are more stable than the rest.

3.       The most numerous nuclei are those with even numbers of both protons and neutrons; the least abundant are those with odd numbers of both protons and neutrons; and the intermediate types are those with odd numbers of one type and even numbers of the other type. High natural abundance is, of course, related to stability. Brown provided information regarding the relative abundances of nuclei in 1949 using information about the elements that make up the sun, the earth, and the stars.

The relative abundances of naturally occurring isotopes with nuclei that contain magic numbers of neutrons or protons are typically larger than 60%. For instance, the relative abundances of the isotopes 88Sr (N = 50), 138Ba (N = 82), and 140Ce (N = 82) are 82.56%, 71:66%, and 88.48%, respectively. The stable end product of the natural radioactive series, Lead 82Pb208 has underline Z= 82 and N=126 both magic numbers.

1.     In contrast to other elements, an element with a magic number of protons typically has a higher number of stable isotopes. For instance, whereas argon (Z = 18) and titanium (Z = 22) have 3 and 5 stable isotopes, respectively, calcium (Z = 20) has 6 stable isotopes. Again, the greatest number of stable isotopes is found in tin with Z = 50. This value is 10, as opposed to 8 for tellurium (Z = 52) and cadmium (Z = 48).

2.     Compared to the nearby isotones, the number of naturally occurring isotones with the magic numbers of neutrons is typically high. For instance, at N = 82 there are seven stable isotones as opposed to three and two at N = 80 and two at N = 84, respectively. Similar circumstances exist at N = 20, 28, and 50, which have 5, 5, and 6 isotones, respectively. These numbers are larger than in the cases of the nearby isotones.

3.     The nuclei with the magic numbers of neutrons typically have low neutron capture cross­sections. The probability of these nuclei acquiring an extra neutron is low because their neutron shells are already full, as seen in Fig. Similar to this, the cross sections for proton capture are small for nuclei with the magic proton numbers.

4.     If the heavy nuclei's disintegration energies are plotted as functions of mass number A for a given Z, a regular fluctuation is typically seen up until the magic neutron number N = 126, at which point there is a sharp discontinuity. This demonstrates the neutron number 126's magical properties.

5.     P-emitters exhibit discontinuities at the magic proton or neutron values

6.     The three lead isotopes, which all have the same magic number Z = 82 of protons in their nuclei, are the stable end products of all three naturally occurring radioactive series.

7.     The earliest excited states of nuclei with magic numbers of neutrons or protons occur at energies higher than those of the nearby nuclei.

 

2.11.             Units

The most commonly used unit is the curie. It was originally based on the rate of decay of a gram of radium. Experiments have yielded the result that there are-about 3.7 x 1010 disintegrations per second per gram of radium. This number is taken as a standard and is called the curie. Thus by definition,

 This is applicable to all types of nuclear disintegrations.

A Curie of activity is a very strong source of radiation.

Thus, one has

and

1 millicurie = 1 mCi = 10-3Ci

1 microcurie = 1μCi = 10-6Ci.

Sometimes one uses another unit for activity, called the rutherford.

Activity can also be defined in terms of N as

 Thing to remember is that a  very short-lived substance gives rise to large activity, even if it is present in minute quantities.

The radiation exposure is measured by the unit called roentgen(R). One roentgen is defined as the quantity of radiation which produces 1.6 × 1012 pairs of ion in 1 gram of air.

2.12.           nuclear stability - neutron- proton ratio

Some nuclei are stable, some are not. A stable nucleus is one that will remain in its current state indefinitely unless an outside agent interacts with it; an unstable nucleus is one that will spontaneously change to another. Various modes of decay will be covered below. In general, stable nuclei have approximately equal number of neutrons as protons, and a strong excess of one or the other will result in an unstable nucleus. The ratio of neutrons to protons in a stable nucleus is thus around 1:1 for small nuclei (Z < 20). The ratio increases slowly with atomic number up to about 1.58 at high Z. There are only two stable nuclei with Z > N (more protons than neutrons): 1H and 3He, each of which has one more proton than it has neutrons.

There are some tendencies, or rules, that stable nuclei observe. By definition A = N + Z, i.e., it is the total number of nucleons in a nucleus.

Stable nuclei of even Z are more numerous than those with odd Z.

Stable nuclei of even N are more numerous than those with odd N.

Stable nuclei of even A are more numerous than those with odd A.

Stable nuclei of even A usually have even Z. Among the exceptions to this rule are the following light, stable nuclei: 2H, 6Li, 10B, and 14N.

Only two stable structures are known for which Z > N: see above.

For any Z there is a range of stable N. At low Z, N ≈ Z; as Z increases, the value of N/Z for which stability occurs gradually rises to around 1.58 for the heaviest stable nuclei, namely, those of lead (Z = 82).

For the most part, alpha and beta decays tend to occur in ways that move a nucleus toward the range of N/Z shown in the figure above. Thus in a typical alpha decay,

236Ra →      222Rn  + α + γ + Q

Z = 88                              86      (number of protons)

N = 138                           136     (number of neutrons)

N / Z = 1.5682                 1.5814         

2.13.           Binding energy

The rest mass of the stable nucleus of a stable atom is always less than the sum of the masses of constituent nucleons. The difference is called the mass defect Δm (i.e., Δm.c2) is utilised in keeping the nucleons bound together. This energy is known as the binding energy. In order to break the nucleus into its constituent nucleons an amount of energy equal to its binding energy has to be supplied to the nucleus. The mass defect per nucleon Δm/A = P, is called the packing fraction of the nucleus.

Atomic mass is the mass of a single atomic particle or molecule. It is the sum of protons and electrons present in the atom of an element. It is expressed in mole. It is simply a collection of nuclides that make up a chemical element. it is a whole number. 

Atomic weight is the ratio of atom of an element. The average weight of an atom is relative to the 1/12 weight of the carbon -12 atom. It is also referred to as relative atomic mass.The value is not necessarily a whole number.

Atomic weight = [Mass(a) isotope(a)]+[Mass(b) isotope(b)]

The nucleons are bound together in a nucleus and the energy has to be supplied in order to break apart the constituents into free nucleons. The energy with which nucleons are bounded together in a nucleus is called as Binding Energy (B.E.). In order to free nucleons from a bounded nucleus this much of energy (= B.E.) is to be supplied.

It is observed that the mass of a nucleus is always less than the mass of constituent (free) nucleons. This difference in mass is called as mass defect and is denoted as Dm.

If mn: mass of a neutron;

mp: mass of a proton

M (Z, A): mass of bounded nucleus

Then, Δm = Z . mp + (A – Z). mn – M (Z, A)

This mass-defect is in form of energy and is responsible for binding the nucleons together. From Einstein's law of inter-conversion of mass into energy:

E = mc2     (c: speed of light; m: mass)

Binding energy,

Generally, Δm is measured in amu units. So let us calculate the energy equivalent to 1 amu. It is calculated in eV (electron volts; 1 eV =1.6 x10–19J)

E (= 1 amu = 1.67 × 10–27 (3×108)2 / 1.6 × 10–19) eV = 931 × 108 eV = 931 MeV

=> B.E. = Δm (931) MeV

There is another quantity which is very useful in predicting the stability of a nucleus called as Binding energy per nucleons.

B.E. per nucleons = Δm (931) / A MeV

Observation from the plot of B.E./nucleons Vs mass number (A):-

(i) B.E./nucleons increases on an average and reaches a maximum of about 8.7 MeV for Aº 50 – 80.

(ii) For more heavy nuclei, B.E./nucleons decreases slowly as A increases. For the heaviest natural element U238 it drops to about 7.5 MeV.

(iii) From above observation, it follows that nuclei in the region of atomic masses 50-80 are most stable.

2.14.           Packing fraction

The packing fraction describes the distribution of nucleons inside the nucleus. The link between the mass defect and the number of nucleons is what it’s called. The mass defect is the difference between the actual isotopic mass (M) and the mass number (M) (A). As a consequence, A is the correct answer.

P= M-A

Where A is the mass number and M is the actual isotopic mass, is an isotope’s packing fraction (P).

The packing fraction might be positive, negative or 0 percent. If the packing fraction is more than one, the nucleus is unstable and will undergo fusion or fission, depending on the packing fraction. The nuclei are particularly stable if the packing fraction is negative and vice versa. In this scenario, mass defects reveal the presence of binding energy. The monoisotopic elements have a mass number that matches the isotopic mass, as shown by the zero-packing fraction.

In nuclear physics, the numbers 2, 8, 20, 28, 50, 82 and other uncommon numbers are employed. “Magic numbers” are what they’re called. The nuclei are deemed to be particularly stable if their atomic number or neutron number equals one of the magic numbers. The nucleus will try to reduce the number of neutrons while increasing the number of protons if the neutron to proton ratio is larger. In a similar vein, a nucleus with a lower neutron-to-proton ratio would try to increase the number of neutrons while lowering the number of protons to improve stability. As a consequence of this process, they will emit radioactive emissions. That is why, in our reactor designs, we use hydrogen isotopes for fusion and uranium for fission.

2.15.           Mass defect.

The nuclear binding energy holds a significant difference between the nucleus’s actual mass and its expected mass depending on the sum of the masses of isolated components.

Hence, energy and mass are related based on the following equation:

E=mc2

Where c is the speed of light. In nuclei, the binding energy is so high that it holds a considerable amount of mass.

The actual mass is less than the sum of individual masses of the constituent neutrons and protons in every situation because energy is ejected when the nucleus is created. This energy consists of mass which is ejected from the total mass of the original components and is called a mass defect. This mass is missing in the final nucleus and describes the energy liberated when the nucleus is made.

Mass defect is determined as the difference between the atomic mass observed (Mo) and expected by the combined masses of its protons (mp, every proton has a mass of 1.00728 AMU) and neutrons (mn, 1.00867 AMU).

Md=(mn+mp)-mo

Bond Energy or Bond-dissociation Energy

We are talking about bond energy and bond-dissociation energy, which are basically measures of the binding energy between the atoms in a chemical bond. Bond energy is the energy that is used to disassemble a molecule into its constituent atoms. It appears in the form of chemical energy released during chemical explosions, the burning of chemical fuel and other processes.

Applications

Binding energy is also applied in determining whether fusion or fission will be favourable. For elements that are lighter than iron-56, the fusion releases energy since the nuclear binding energy rises with the hike in mass. Elements that are heavier than iron-56 release energy on fission since the lighter elements consist of higher binding energy. Hence, there exists a peak at iron-56 according to the nuclear binding energy curve.

2.16.           Simple calculations involving mass defect and B.E., decay constant and t1/2 and radioactive series.

Problem 1:-:

If mass of proton = 1.008 amu and mass of neutron = 1.009 amu, then the binding energy per nucleon for 4Be9 (mass = 9.012 amu) will be:

(A) 0.0672 MeV                (B) 0.672 MeV

(C) 6.72 MeV                   (D) 67.2 MeV

Solution:-

Mass defect,

Δm     = (4 × 1.008 + 5 × 1.009) – 9.012

= 9.077 – 9.012 =0.065 amu

BE/A = 0.065 × 931 / 9 = 6.72 MeV

Problem 2:-:

The energy released in the following b-decay process will be:

Given that,

mn = 1.6747 × 10–27 kg 

mp = 1.6725 × 10–27 kg

me = 0.00091 × 10–27 kg 

(A)    0.931 MeV                 (B)    0.731 MeV

(C)    0.511 MeV                 (D)    0.271 MeV

Solution:-

Mass defect Δm = (1.6747 – 1.6725 – 0.0091) × 10–27 = 0.0012 × 10–27 kg

ΔE = 0.0012 × 10–27 × (3 × 108)2 / 1.6 × 10–12 = 0.731 MeV

Problem 3:-:

 If the mass of 3Li7 is 7.01653 amu, then find out binding energy per nucleon for 3Li7 .

(A)    5.6 MeV                     (B)    39.25 MeV

(C)    1 MeV                        (D)    zero.

Solution:-

E = ΔE / A = Δm × 931 / A MeV 

Δm     = (3mp + 4mn) – mass of Li7

= (3 × 1.00759 + 4 × 1.008898) – 7.01653

= 0.04216

ΔE      = 0.04216 × 931 / 7 = 39.25 / 7 = 5.6 MeV

Problem 4:-:

How much energy is released in the following reaction?

1H2 + 1H2 = 2He4

If the B.E./Nucleon of 1H2 and 2He4 are 1.123 MeV and 7.2 MeV respectively.

(A)    12 MeV                      (B)    24.3 MeV

(C)    36 MeV                      (D)    zero

Solution:-

B. E. of 1H2,

ΔE = 1.125

E = A × ΔE

E = 2 × 1.125 = 2.25 MeV

B.E. of two 1H2 = 2.25

Ed = 4.5 MeV

B.E. of an α -particle = 4 × 7.2

Ea = 28.8

Energy released ER = Ea – Ed

ER = 28.8 – 4.5 = 24.3 MeV

From the above observation we conclude that, option (B) is correct.

PROBLEM - 5

Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon for a 6C12 nucleus. Nuclear mass of 6C12=12.000000 a.m.u., mass of hydrogen nucleus =1.007825 a.m.u. and mass of neutron =1.008665 a.m.u.

Solution

Given,

Mass of one proton = 1.007825 a.m.u

Mass of one neutron= 1.008665 a.m.u

Nuclear mass of 6C12 = 12 a.m.u

(i) 6C12 has 6 proton, 6 electron and 6 neutron.

Mass of nucleus = Mass of 6 proton + Mass of 6 neutron

=(6×1.007825)+(6×1.008665)

=12.09894u

Mass defect (Δm) =12.09849u−12u=0.098931u

(ii) Binding Energy = Mass Defect × 931.5MeV

=0.09849u×931.5MeV/u=92.15MeV

(iii) Binding Energy per Nucleon

= Binding Energy / Number of Nucleons

Number of nucleon = Mass Number = 12

So, Binding Energy per nucleon =92.1512=7.68MeV

 

PROBLEM- 6  After 24 hours, only 0.125 g out of the initial quantity of 1g of a radioisotope remains behind. what is half-life period?

PROBLEM-7 Half-life period of a radioactive element is 100 seconds. Calculate the disintegration constant and average life period. How much time will it take for 90% decay?

2.17.           Isotopes – uses

a) Study of reaction mechanism

Mechanism of photosynthesis in plants

A small quantity of Radioactive CO 2 containing radioactive oxygen O18 is mixed with ordinary carbondioxide and the process is carried out. It has been found that oxygen gas evolved along with sugar formation is non-radioactive. Therefore O2 produced comes from water and not from carbondioxide. So the correct mechanism is as follows.

6CO2 + 6H2OC6H12O6 + 6O2

Study of hydrolysis of ester

By labelling oxygen, the mechanism of ester hydrolysis can be studied by using water labelled with O18. The hydrolysis of an ester by water enriched with radioactive oxygen is indicated as :

Therefore it is the acid and not alcohol produced which is radioactive confirming the above mechanism.

2.18.           Nuclear energy; nuclear fission and fusion

Nuclear Fission

Nuclear fission is the process in which a heavy nucleus breaks up into two lighter nuclei of almost equal size with the release of an enormous amount of energy. This type of nuclear fission reaction was first observed by German Chemists Otto Hahn, F.Strassman and Meitner by bombarding 92U235 with slow moving neutrons. The process is usually accompanied by emission of neutrons. The nuclear fission has been produced in heavy nuclei such as 235U,238U, 232Th by neutrons, protons, deuterons.

Mechanism of fission

In the fission process, the heavy nucleus absorbs a neutron and forms an unstable compound nucleus. The compound nucleus then breaks up more or less in the middle to give fission product.

Example

A typical example of the fission process in the fission of uranium by neutrons is explained by the following equation.

92U235 + 0n156Ba141 + 3 0n1 + 200 MeV

Further, the neutrons released (say three) from the fission of first uranium atoms can hit three other uranium atoms. In this way a chain reaction is set up resulting into the liberation of an enormous amount of energy. In the case of nuclear fission, 92U236 formed breaks up in several ways.

This fission process is self multiplying process and hence a tremendous amount of energy is released in a very short interval of time. Therefore, explosion takes place. Atom bomb is based on nuclear fission process.

Energy released in nuclear fission reaction

92U235  +0n1 42Mo95+57La139+20n1+ 71e0

The isotopic mass of U235            =235.118 amu

The isotopic mass of 42Mo95             = 94.936 amu

The isotopic mass of 57La139         = 138.95 amu

The isotopic mass of 0n1              =1.009 amu

: 235.118 + 1.009 → 94.936 + 138.95 + 2 x 1.009

236.127 amu → 235.906 amu

: The mass converted into energy is

= (236.127 - 235.906) amu

= 0.213 amu

Since 1amu (atomic mass unit) = 931 MeV, for one 235U fission energy released = 0.213 x 931.48 = 200 MeV

Nuclear Power Generator

A nuclear reactor or nuclear power generator is a kind of furnace for carrying out the controlled fission of a radioactive material like U235 for producing power.

The core of the nuclear reactor produces heat through nuclear fission. Heavy water at high pressure takes heat away from the core. In the heat exchanger, the heavy water inside the reactor gives up its heat to water outside the reactor, which boils to form steam. The steam is taken away to drive turbines that make electricity. In Tamilnadu atomic power stations generating electricity are situated at Kalpakkam and Koodamkulam.

Nuclear Fusion

When lighter nuclei moving at a high speed are fused together to form a heavy nucleus, the process is called nuclear fusion.

In fusion reaction, the mass of heavier nucleus formed is less than the total mass of two lighter nuclei. Thus, just like a fission reaction, the source of energy in a fusion reaction is also the disappearance of mass, which gets converted into energy.

Nuclear fusion reaction takes place at very high temperature of about 108K. Therefore, this reaction is called thermonuclear reaction.

1H2     +        1H3     →      2He4   +        0n1 +   Energy

Deuterium Tritium            Helium

The Mass loss is equal to 0.018 amu and the corresponding energy released is 1.79 x 109 KJmol-1.

Hydrogen Bomb

The highly destructive hydrogen bomb is also based on the fusion reactions of hydrogen to form helium producing large amount of energy. Hydrogen bomb consists of an arrangement for nuclear fission in the centre surrounded by a mixture of deuterium (1H2) and lithium isotope (3Li6). Fission reaction provides the high temperature necessary to start the fusion.

Fusion reactions take place in hydrogen bomb.

2.19.           major nuclear reactors in India

Nuclear Power Plants in India – Operational

Name Of Nuclear Power Station

Location

Operator

Capacity

Kakrapar Atomic Power Station – 1993

Gujarat

NPCIL

440

(Kalpakkam) Madras Atomic Power Station – 1984

Tamil Nadu

NPCIL

440

Narora Atomic Power Station- 1991

Uttar Pradesh

NPCIL

440

Kaiga Nuclear Power Plant -2000

Karnataka

NPCIL

880

Rajasthan Atomic Power Station – 1973

Rajasthan

NPCIL

1,180

Tarapur Atomic Power Station – 1969

Maharashtra

NPCIL

1,400

Kudankulam Nuclear Power Plant – 2013

Tamil Nadu

NPCIL

2,000

Nuclear power in India has suffered from generally low capacity factors. As of 2021, the lifetime weighted energy availability factor of the Indian fleet is 66.1%. However, capacity factors have been improving in recent years. The availability factor of Indian reactors was 74.4% in the years 2019–2021. One of the main reasons for the low capacity factors is lack of nuclear fuel.

India has been making advances in the field of thorium-based fuels, working to design and develop a prototype for an atomic reactor using thorium and low-enriched uranium, a key part of India's three stage nuclear power programme.

2.20.          Radiation hazards, disposal of radioactive waste and safety measures.

TACKLING RADIOACTIVE WASTES EFFICIENTLY

Any activity related to the nuclear fuel cycle, that produces or uses radioactive materials generates radio-active waste. The management of radiation emitting radioactive material is a matter of concern and is what sets nuclear wastes apart. Public acceptance of nuclear energy largely depends on the public assurance for safe management of radioactive wastes. Not all nuclear wastes are particularly hazardous or difficult to manage as compared to other toxic industrial wastes.

Safe management of radioactive waste has been accorded high priority right from the inception of our nuclear energy program. In accordance with international guidelines, a coherent comprehensive and consistent set of principles and standards are being practiced all over the world for waste management system. Radioactive waste would be managed in a manner so as not to cause any undue radiation risk to the workers, the public (present as well as future generation) and the environment.

Management of these wastes covers the entire range of activities right from handling, treatment, conditioning, transport, storage and disposal. 

The recent technological developments in India realize the recovery of valuable radionuclide from radioactive waste for societal application besides ensuring the highest level of safety in the management of radioactive waste.

UNDERSTANDING RADIOACTIVE WASTES

Radioactive wastes are generated during various operations of the nuclear fuel cycle as well as production and use of radionuclide for various societal applications. The activities like mining and processing of uranium ore, fabrication of nuclear fuel, generation of power in nuclear reactor, processing of spent nuclear fuel, management of radioactive waste, production and use of radionuclide for various industrial and medical applications, research associating with radioactive material etc. generates the different types of radioactive waste. Radioactive waste can be in gas, liquid or solid form, and its level of radioactivity can vary. The waste can remain radioactive for a few hours or several months or even hundreds of thousands of years. Depending on the level and nature of radioactivity, radioactive wastes can be classified as exempt waste, Low & Intermediate level waste and High Level Waste. The most important and advantageous property of radioactive waste is 'Its radioactive hazard potential reduces with time depending on the half lives of radionuclide present in the waste'. Such feature differentiates them significantly from conventional chemical or industrial waste, hazard potential or toxicity of which does not alter with time and remains constant till its transformation to other suitable form.

LOW AND INTERMEDIATE LEVEL WASTE (LILW)

Low and Intermediate Level Waste (LILW) radioactive waste are generated in radiation facilities and nuclear fuel cycle operations ranging from uranium processing, fuel fabrication, nuclear power plants, research reactors, radiochemical facilities and fuel reprocessing. LILW have generally high volumes and low levels of radioactivity. They are segregated based on their physical nature and different management techniques have been established based on their nature for their effective treatment. They are further classified based on their radioactivity as well as also based on half life of radionuclide, as short lived and long lived wastes. Significant quantum of LILW of diverse nature gets generated in different nuclear installations.

They are essentially of two types

Primary Wastes comprising of radioactively contaminated equipment (metallic hardware) spent radiation sources etc.

Secondary wastes resulting from different operational activities, protective rubber and plastic wears, cellulosic and fibrous material, organic ion exchange resins filter cartridges and others.

HIGH LEVEL WASTE

High level radioactive liquid waste (HLW) containing most (~99%) of the radioactivity in the entire fuel cycle is produced during reprocessing of spent fuel. A major stream of this waste is the aqueous radioactive waste generated from the first cycle extraction of the spent fuel processing. Also solid waste not suitable for disposal in near surface disposal facilities due to significant concentration of long-lived radionuclides or decay heat above the prescribed limits may also need to be regarded as high level waste. Issue of the long lived radioactive waste has been the focal point of debate for the success of nuclear power. Planning for management of HLW thus takes into account the need for their effective isolation from the biosphere and their continuous surveillance for extended periods of time spanning several generations. To meet this objective in the long term, waste isolation systems comprising multiple barriers are employed so as to prevent the movement of radionuclides back to the human environment.

MANAGEMENT OF RADIOACTIVE WASTES

Utmost emphasis is given to waste minimization, and volume reduction in the choice of processes and technologies adopted in radioactive waste management plants. As a waste management philosophy, no waste in any physical form is released / disposed to the environment unless the same is cleared, exempted or excluded from regulations. A comprehensive radioactive waste management is established taking into account the operational capability for the management of radioactive waste and an independent regulatory capability for its overview.

In consideration to the primary objective of protecting human health, environment and future generations, the overall philosophy for safe management of radioactive wastes in India, is based on the concept of

  • Delay and Delay
  • Dilute and Disperse
  • Concentrate and Contain
  • Recycle and Reuse

Effective management involves segregation, characterization, handling, treatment, conditioning and monitoring prior to final disposal.

SOLID WASTE

Substantial amount of LIL wastes of diverse nature, gets generated in different nuclear installations as radioactive solid waste. Treatment and conditioning of solid wastes are practiced, to reduce the waste volume in ways, compatible to minimizing the mobility of the contained radioactive materials. A wide range of treatment and conditioning processes are available today with mature industrial operations involving several interrelated steps and diverse technologies.

Proper disposal of Solid waste is essential to ensure protection of the health and safety of the public and quality of the environment including air, soil, and water supplies. Radiological hazards associated with short lived wastes < 30 years half life get significantly reduced over a few hundred years by radioactive decay. Disposal of waste is carried out in specially constructed engineering modules such as stone lined trenches, reinforced concrete trenches and tile holes at Near Surface Disposal Facility (NSDF). These disposal structure are located both above and under-ground in access - controlled areas and are designed based on multi barrier principle for ensuring effective containment and isolation of the radioactivity till it decays to innocuous level. The NSDFs where the disposal structures are located are kept under constant surveillance with the help of bore-wells laid out in a planned manner by routinely monitoring the underground soil and water samples to confirm effective confinement of radioactivity present in the disposed waste.

The high level solid wastes contain large concentration of both short and long lived radionuclide's, warranting high degree of isolation from the biosphere and usually calls for final disposal into Geological Disposal Facility (GDF). A key idea was that long-term disposal would be best carried out by identifying suitable sites at which the waste could be buried, a process called deep geological disposal.

LIQUID WASTE (LIL)

Liquid waste streams are pre-treated by various techniques, such as filtration, adsorption, chemical treatment, evaporation, ion exchange; reverse osmosis etc., prior to immobilization in suitable matrix depending upon the nature, volume & radioactivity content.

GASEOUS WASTE

Gaseous waste is treated at the source of generation. Various techniques involoving adsorption on activated charcoal, absorption / scrubbing, filtration by high efficiency particulate air filter etc., are used for effective treatment of gaseous waste

MANAGEMENT OF HIGH LEVEL WASTE

High level radioactive waste gets generated during reprocessing of spent fuel. Most of the radioactive isotopes in high level waste emit large amounts of radiation and have long half-lives. The management of high level waste in the Indian context, is carried out in the following three stages:

1.     Immobilisation of high level liquid waste into inert vitrified borosilicate glasses through process called 'vitrification'.

2.     Engineered interim storage of the vitrified waste for passive cooling & surveillance over a period of time, qualifying it for subsequent disposal.

3.     Disposal of the vitrified waste in a deep geological repository.

VITRIFICATION

India is one of the few countries to have mastered the technology of vitrification. Over the years BARC has developed the technology for vitrification of HLW. India has a unique distinction of having operating vitrification plant at Trombay, Tarapur and Kalpakkam.

In our existing plant at Trombay vitrification process is essentially batch operation consisting of heating and fusing of pre-concentrated waste and glass forming additives and is carried out in Induction Heated Metallic Melter based on induction heating.

While the plant at Trombay is based on pot glass technology, the concept of Joule Heated Ceramic Melter (JHCM) is utilized at the facility at Tarapur. The Joule Melter Technology is essentially a single step process, where immobilisation of HLW in a borosilicate glass matrix is achieved in a refractory-lined melter. The Joule Heated Ceramic Melter (JHCM) process exploits the high temperature behaviour of glass whereby it becomes an electrical conductor at elevated temperatures and favourable changes in its viscosity near the pour point, helps in product withdrawal and shut off. The distinctive features of the Advanced Vitrification System (AVS) of Tarapur and Waste Immobilisation Plant, Kalpakkam, employing JHCM for vitrification of HLW, are increased throughput, availability of higher furnace temperature and minimum dependence on operator skills.

Cold Crucible Induction Melter (CCIM) is emerging as a futuristic technology for vitrification of high level liquid waste. Besides being compact and advantageous as in-cell equipment, it offers flexibility, susceptibility to treat various waste forms with better waste loading and enhanced melter life. The CCIM is manufactured from contiguous segments forming a cylindrical volume, but separated by a thin layer of electrically insulating material. The number and the shape of the segments and the insulating gap between them must be optimized to minimize the power dissipation by induced currents in the crucible, while ensuring cooling of the crucible.

  • INTERIM STORAGE OF VITRIFIED WASTE

The vitrified product is encapsulated in suitable containers and over packs and stored for dissipation of radioactive decay, heat and surveillance for a period of 15-20 years. Sufficient data can be generated on the product behavior and the radiation and thermal conditions of the product are expected to get stabilized to a level where transport of the product becomes viable. On the basis if safety and techno-economic considerations, a natural draught air cooling system has been designed for the storage vault.

WEALTH FROM WASTE

High level radioactive liquid waste contains various useful fission product such as 137Cs, 90Sr,106Ru etc., which have many industrial as well as medical applications. The energy associated with these isotopes can be used for blood irradiation, food preservation, sewage treatment, therapeutic applications, brachy therapy & various other industrial applications. Separation and recovery of these useful isotopes from radioactive waste and their deployment for societal application makes the waste as a material of resource.

137CESIUM GLASS PENCILS FOR IRRADIATION

137Cs can be used as a prominent alternate irradiation source to 60C° for various applications like blood irradiator, food irradiator, irradiation of sewage sludge etc.

Due to longer half-life of 137Cs as compare to 60Co, the radiation sources need to be replaced at lesser frequency. 137Cs is available in large quantity in radioactive waste as one of the principal fission product.

In-house development of selective extractants and their deployment has resulted into recovery of bulk of 137Cesium from waste. The recovered 137Cs solution is converted into non- dispersible cesium glass pencil to be used as blood irradiator.

Few lac Ci of 137Cs have been recovered successfully and are converted into Cs glass pencils each having activity of 2.0 to 5.0 Ci/gm of 137Cs at Waste Immobilization Plant Trombay. These pencils have been supplied to various hospitals through BRIT after ensuring rigorous quality assurance.

Research and Development is being pursued to make use of Cs glass pencils for other irradiation process such as food irradiation.

90STRONIUM FOR MILKING OF 90YTTRIUM FOR RADIOPHARMACEUTICAL APPLICATION

90Sr, another isotope present in waste, decays to 90Y by beta decay having its application as a radiopharmaceutical product for therapeutic use during treatment of cancer. In-house developed strontium selective extractant has been successfully deployed for separation/ recovery of strontium from HLW and converting into Yttrium generator. 90Y is milked out from purified 90Sr using in-house developed membrane technology and supplied for radiopharmaceutical application.

106Ru FOR EYE CANCER TREATMENT

106Ru has an important application for eye cancer treatment as a brachy therapy. Till date, 106Ru plaques are imported. Technology for recovery of 106Ru from nuclear waste and fabrication of 106Ru containing silver plaque has been successfully developed as an import substitute for eye cancer treatment along with cost effectiveness. Ru plaques, containing about 300-600 microcurrie of Ru-106 activity, are produced and supplied to various eye hospitals through BRIT for eye cancer treatment. The indigenously developed Ru-106 eye plaques are cost effective and thier performance is at par the international standard.

Safe management of radioactive waste has been accorded high priority right from the inception of our nuclear energy program. As a result of rugged design with 'defense in depth' concept, well established practices and safety review by independent agency, an excellent track record for safe management of radioactive waste in India has been demonstrated for more than five decades. Consistent efforts in R&D has enabled indigenous development of novel processes and technologies in the field of management of radioactive waste and their deployment to realise the waste volume minimization, effective isolation of radionuclide in engineered matrix, minimization of discharges and extracting wealth from waste by separating useful radionuclide from radioactive waste for societal applications. Such developments enable the country to be front-runner in the field of radioactive waste management in the world.

 


 

UNIT-IV

3.   Halogen derivatives Aliphatic halogen derivatives

When one or more hydrogen atoms of aliphatic or aromatic hydrocarbons are replaced by the corresponding number of halogens like fluorine, chlorine, bromine or iodine, the resultant compounds are called either haloalkanes or halo arenes. They serve as starting materials for many organic synthesis.

Halogen substituted organic compounds are widely spread in nature and find application in our day to day life as well as in industry. Certain compounds like chloramphenicol produced by soil microbes are used in the treatment of typhoid; chloroquine is used in the treatment of malaria, halothane is used as an anesthetic, and halogenated solvents like trichloroethylene are used for cleaning electronic equipments.

Mono halogen derivatives of alkanes are called haloalkanes. Haloalkanes are represented by general formula R - X, Where, R is an alkyl group (CnH2n+1) - and X is a halogen atom (X=F, Cl, Br or I). Haloalkanes are further classified into primary, secondary, tertiary haloalkane on the basis of type of carbon atom to which the halogen is attached.

 

3.1. Nomenclature and classes of alkyl halides

Common system

In the common system, haloalkanes are named as alkyl halides. It is derived by naming the alkyl group followed by the halide.

IUPAC system

Let us write the IUPAC name for the below mentioned haloalkanes by applying the general rules of nomeclature

3.2.             Physical properties

1. Pure haloalkanes are colourless. Bromo and iodo alkanes are coloured in the presence of light.

2. Haloalkanes having one, two or three carbon atoms are in the gaseous state at normal temperature. Haloalkanes having more than three carbon atoms are liquids or solids.

3. Boiling point and Melting point

Haloalkanes have higher boiling point and melting point than the parent alkanes having the same number of carbons because the intermolecular forces of attraction (dipole - dipole interaction and vander Waals forces) are stronger in haloalkane.

The boiling point and melting point of haloalkanes decreases with respect to the helogen in the following order.

Example

CH3I > CH3Br > CH3Cl > CH3F

The boiling points of chloro, bromo and iodo alkanes increase with the increase in the number of halogen atoms.

For Example:

CCI4 > CHCI3 > CH2CI2 > CH3CI

4.  The boiling point and melting point of mono haloalkane increase with the increase in the number of carbon atoms.

Example CH3CH2CH2Cl > CH3CH2Cl > CH3Cl

5. Among isomeric alkyl halides the boiling point decreases with the increase in branching in the alkyl group; with increase in branching, the molecule attains spherical shape with less surface area. As a result the inter molecular forces become weak, resulting in lower boiling points.

6. Solubility

Haloalkanes are polar covalent compounds soluble in organic solvents, but insoluble in water because they cannot form hydrogen bonds with water molecules

7. Density

The density of liquid alkyl halides are higher than these of hydrocarbons of comparable molecular weight.

3.3.             Chemical reactions. Nucleophilic substitution reactions – SN1, SN2 and SNi mechanisms with stereochemical aspects and effect of solvent.

Nature of C - X bond in haloalkane

Carbon halogen bond is a polar bond as halogens are more electro negative than carbon. The carbon atom exhibits a partial positive charge (δ+) and halogen atom a partial negative charge (δ-).

The C -X bond is formed by overlap of sp3 orbital of carbon atom with half filled p-orbital of the halogen atom. The atomic size of halogen increases from fluorine to iodine, which increases the C - X bond length. Larger the size, greater is the bond length, and weaker is the bond formed. The bond strength of C - X decreases from C - F to C - I in CH3X. The changes in the value of bond length, bond enthalpy and bond polarity, as we move from C -F to C -I.

Haloalkanes are one of the most reactive classes of organic compounds. Their reactivity is due to the presence of polar carbon - halogen bond in their molecules. The reactions of haloalkane may be divided into the following types

·       Nucleophilic substitution reactions

·       Elimination reactions

·       Reaction with metals

·       Reduction

1) Nucleophilic substitution reactions

We know that the C6+ - X6- present in halo alkane is polar and hence the nucleophilic reagents are attracted by partially positively charged carbon atoms resulting in substitution reactions.

Reaction with aqueous alkali or moist silver oxide.(Hydrolysis)

Haloalkane reacts with aqueous solution of KOH or moist silver oxide (Ag2O/H2O) to form alcohols.

i)  Reaction with alcoholic ammonia (Ammonolysis)

Haloalkanes react with alcoholic ammonia solution to form alkyl amines.

Example

However, with excess of halo alkane, secondary and tertiary amines along with quartenary ammonium salts are obtained

Ambident Nucleophiles

Nucleophiles such as cyanide and nitrite ion which can attack nucleophilic centre from two sides of the nucleophile are called ambident nucleophiles. These nucleophiles can attack with either of the two sides depending upon the reaction conditions and the reagent used.

ii)  Reaction with alcoholic KCN

Haloalkanes react with alcoholic KCN solution to form alkyl cyanides.

Example

iii)  Reaction with alcoholic AgCN

Haloalkanes react with alcoholic AgCN solution to form alkyl isocyanide.

Example

iv) Reaction with sodium or potassi­um nitrite

Haloalkanes react with alcoholic solution of NaNO2 or KNO2 to form alkyl nitrites.

Example

v) Reaction with silver nitrite

Haloalkanes react with alcoholic solution of AgNO2 to form nitro alkanes.

v) Reaction with silver nitrite

Haloalkanes react with alcoholic solution of AgNO2 to form nitro alkanes.

Example

vi) Reaction with sodium or potassi­um hydrogen sulphide

Haloalkanes react with sodium or potassium hydrogen sulphide to form thio alcohols.

Example

vii) Williamson ether synthesis

Haloalkane, when boiled with sodium alkoxide gives corresponding ethers.

Example

This method can be used to prepare mixed (unsymmetrical) ethers also.

Mechanism of Nucleophilic substitu­tion reaction

The mechanism of nucleophilic substitution reaction is classified as

a) Bimolecular Nucleophilic

substitution reaction (SN2)

b) Unimolecular Nucleophilic substitution reaction (SN1)

The rate of SN2 reaction depends upon the concentration of both alkyl halide and the nucleophile.

Rate of reaction

= k2 [alkylhalide][nucleophile]

It follows second order kinetics and occurs in one step.

This reaction involves the formation of a transition state in which both the reactant molecules are partially bonded to each other. The attack of nucleophile occurs from the back side (i.e opposite to the side in which the halogen is attacked). The carbon at which substitution occurs has inverted configuration during the course of reaction just as an umbrella has tendency to invert in a wind storm. This inversion of configuration is called Walden inversion; after paul walden who first discovered the inversion of configuration of a compound in SN2 reaction.

SN2 reaction of an optically active haloalkane is always accompanied by inversion of configuration at the asymmetric centre. Let us consider the following example

When 2 - Bromooctane is heated with sodium hydroxide, 2 - octanol is formed with invesion of configuration. (-)– 2 – Bromo octane is heated with sodium hydroxide (+) – 2 – Octanol is formed in which   – OH group occupies a position opposite to what bromine had occupied,

a.     (-) 2 - Bromo octane

b.     Transition State

c.     (+) 2 - Octanol (product)

SN1 Mechanism

SN1          stands for unimolecular

nucleophilic substitution

‘S’ stands for substitution

‘N’ stands for nucleophilic

‘1’ stands for unimolecular (one molecule is involved in the rate determining step)

The rate of the following SN1 reaction depends upon the concentration of alkyl halide (RX) and is independent of the concentration of the nucleophile (OH-).

Hence Rate of the reaction

= k[alkyl halide]

R-Cl + OH- → R - OH + Cl-

This SN1 reaction follows first order kinetics and occurs in two steps.

We understand SN1 reaction mechanism by taking a reaction between tertiary butyl bromide with aqueous KOH.

This reaction takes place in two steps as shown below

Step - 1 Formation of carbocation

The polar C - Br bond breaks forming a carbocation and bromide ion. This step is slow and hence it is the rate determining step.

The carbocation has 2 equivalent lobes of the vacant 2p orbital, so it can react equally rapidly from either face

Step - 2

The nucleophile immediately reacts with the carbocation. This step is fast and hence does not affect the rate of the reactions.

As shown above, the nucleophilic reagent OH- can attack carbocation from both the sides.

In the above example the substrate tert-butyl bromide is not optically active, hence the obtained product is optically inactive. If halo alkane substrate is optically active then, the product obtained will be optically inactive racemic mixture. As nucleophilic reagent OH- can attack carbocation from both the sides, to form equal proportion of dextro and levorotatory optically active isomers which results in optically inactive racemic mixture.

Example

Hydrolysis of optically active 2 - bromo butane gives racemic mixture of ± butan-2-ol.

The order of reactivity of haloalkanes towards SN1 and SN2 reaction is given below.

3.4.             Di, Tri & Tetra Halogen derivatives:

Carbon compounds containing more than one halogen atoms are called poly halogen compounds. Some of the important poly halogen compounds are described below.

They are classified as

a) gem - dihalides

CH3CHCl2

Ethylidene chloride 1,1 - Dichloro ethane

 Isopropylidene chloride (or) Isopropylidene dichloride 2,2-Dichloropropane

b)  vic - dihalides

For Example

 

3.5.             Preparation

a)  gem- dihalides

Ethylidene dichloride (1, 1 - Dichloro ethane) is prepared by

(i)  Treating acetaldehyde with PCl5

(ii)  Adding hydrogen chloride to acetylene

 

b)  vic- dihalides

Ethylene dichloride (1, 2 - Dichloro ethane) is prepared by the following methods.

i)  Addition of chlorine to ethylene

ii) Action of PCl5 (or HCl) on ethylene glycol

3.6.             Properties

Physical Properties

i)  They are sweet smelling, colourless liquids having relatively high boiling points.

ii)  The boiling point of ethylidene chloride is less than that of ethylene dichloride.

Chemical properties

1) Hydrolysis with aqueous NaOH or KOH

Gem-Dihalides, on hydrolysis with aqueous KOH give an aldehyde or a ketone vic-Dihalides, on hydrolysis with aqueous KOH gives glycols.

This reaction can be used to distinguish the gem- Dihalides and vic- Dihalides.

2) Reaction with Zinc (Dehalogenation)

Gem- Dihalides and vic- Dihalides on treatment with zinc dust in methanol give alkenes.

 

3) Reaction with Alcoholic KOH (Dehydrohalogenation)

gem- Dihalides and vic- Dihalides on treatment with alcoholic KOH give alkynes.

 

 

Methylene chloride (Di chloromethane) Preparation

Methylene chloride is prepared by the following methods

1) Reduction of chloroform

a) Reduction of chloroform in the presence of Zn + HCl gives methylene chloride.

b) Reduction of chloroform using H2/Ni

2) Chlorination of methane

Chlorination of methane gives methylene chloride

 

Uses of methylene chloride

Methylene chloride is used as

1)  aerosol spray propellant

2)  solvent in paint remover

3)  process solvent in the manufacture of drugs

4)  a metal cleaning solvent

TRIHALOALKANE

Trihaloalkanes are compounds obtained by replacing three hydrogen atoms of a hydrocarbon by three halogen atoms.

Example

CHCl3                  CHI3

Chloroform        Iodoform

1) CHLOROFORM

Chloroform is an important trihaloalkane. Dumas named CHCl3 as chloroform as it gives formic acid on hydrolysis.

Preparation: Chloroform is prepared in the laboratory by the reaction between ethyl alcohol with bleaching powderfollowed by the distillation of the product chloroform. Bleaching powder act as a source of chlorine and calcium hydroxide. This reaction is called haloform reaction. The reaction proceeds in three steps as shown below.

Step - 1: Oxidation

CH3CH2OH + Cl2                    CH3CHO + 2HCl

Ethyl alcohol                         Acetaldehyde

Step - 2: Chlorination

CH3CHO + 3Cl2                      CCl3CHO + 3HCl

Acetaldehyde                         Trichloro acetaldehyde

Step - 3: Hydrolysis

2CCl3CHO + Ca(OH)2             2CHCl3 + (HCOO)2 Ca

Chloral                                  chloroform

Physical properties

(i)              Chloroform is a colourless liquid with peculiar sickly smell and a burning taste

(ii)            The vapours of chloroform when inhaled it causes unconsciousness (depress the central nervous system) and hence it is used as an anaesthetic.

Chemical properties

1)  Oxidation

Chloroform undergoes oxidation in the presence of light and air to form phosgene (carbonyl chloride)

Since phosgene is very poisonous, its presence makes chloroform unfit for use as anaesthetic.

 

 

2)  Reduction

Chloroform undergoes reduction with zinc and HCl in the presence of ethyl alcohol to form methylene chloride.

3)  Nitration

Chloroform reacts with nitric acid to form chloropicrin. (Trichloro nitro methane)

It used as an insecticide and soil sterilising agent.

4)  Carbylamine reaction

Chloroform reacts with aliphatic or aromatic primary amine and alcoholic caustic potash, to give foul smelling alkyl isocyanide (carbylamines)

CH3NH2          + CHCl3+ 3KOH        CH3NC+3KC1+3H2O

Methylamine   Chloroform                          Methylisocyanide

This reaction is used to test primary amine.

TETRA HALOALKANE

Carbon tetrachloride is a good example for tetra haloalkane Carbon tetrachloride

Preparation

1.  Chlorination of methane

The reaction of methane with excess of chlorine in the presence of sunlight will give carbon tetrachloride as the major product.

2. Action of carbondisulphide with chlorine gas

Carbon disulphide reacts with chlorine gas in the presence of anhydrous AlCl3 as catalyst giving carbon tetrachloride

Physical properties

(i) Carbon tetrachloride is a colourless liquid with its specific smell

(ii) It is insoluble in water and soluble in organic solvents

Chemical properties

(i)  Hydrolysis

Carbon tetrachloride reacts with hot water or with hot water vapour producing the poisonous gas, phosgene.

 

 

(ii)  Reduction

Carbon tetrachloride is reduced by iron powder in dilute HCl medium to form chloroform

Freons (CFC)

The chloro fluoro derivatives of methane and ethane are called freons.

Nomenclature

Freon is represented as Freon-cba

Where c = number of carbon atoms – 1

b = number of hydrogen atoms + 1

a = total number of fluorine atoms

Example

Formula

C-1

H+1

F

Name

CFC13

1-1=0

0+1 = 1

1

Freon-11

CF2C12

1-1=0

0+1 = 1

2

Freon-12

C2F2CI4

2-1=1

0+1 = 1

2

Freon-112

C2F3Cl 3

2-1=1

0+1 = 1

3

Freon-113

Freon – 12 is prepared by the action of hydrogen fluoride on carbon tetrachloride in the presence of catalylic amount of antimony pentachloride. This is called swartz reaction.

Physical properties

Freons are highly stable, unreactive, non corrosive, non toxic, easily liquefiable gases.

Uses:

(i)              Freons are a used as refrigerants in refrigerators and air conditioners.

(ii)            It is used as a propellant for aerosols and foams

(iii)          It is used as propellant for foams to spray out deodorants, shaving creams, and insecticides.

DDT (p,p’-dichloro diphenyl trichloro ethane)

DDT, the first chlorinated organic pesticide was prepared in 1873, and in 1939 Paul Muller discovered the effectiveness of DDT as an insecticide. He was awarded Noble prize in medicine and physiology in 1948 for this discovery.

DDT can be prepared by heating a mixture of chlorobenzene with chloral (Trichloro acetaldehyde) in the presence of Conc.H2SO4.

 

3.7.             Aromatic halogen compounds

Haloarenes are the compounds in which the halogen is directly attached to the benzene ring.

3.8.             Nomenclature

In the IUPAC nomenclature, the halo arenes are named by adding prefix halo before the name of the aromatic hydrocarbon. For naming disubstituted arenes, the relative position of the substituent 1,2; 1,3 and 1,4 are indicated by the prefixes ortho, meta and para, respectively.

For poly haloarenes the numbering should be done in such a way that the lowest possible number should be given to the substituents and the name of the halogens are arranged in alphabetic order.

Nomenclature can be well understood from the following examples.

3.9.             Preparation

1) Direct halogenation

Chlorobenzene is prepared by the direct chlorination of benzene in the presence of lewis acid catalyst like FeCl3

2) From benzene diazonium chloride

Chloro benzene is prepared by Sandmeyer reaction or Gattermann reaction using benzene diazonium chloride.

(i) Sandmeyer reaction

When aqueous solution of benzene diazonium chloride is warmed with Cu2Cl2 in HCl gives chloro benzene

3) Preparation of iodobenzene

Iodobenzene is prepared by warming benzene diazonium chloride with aqueous KI solution.

4) Preparation of fluorobenzene

Fluoro benzene is prepared by treating benzenediazonium chloride with fluoro boric acid. This reaction produces diazonium fluoroborate which on heating produces   fluorobenzene. This reaction is called Balz – schiemann reaction.

5) Commercial preparation of chloro benzene (Raschig process)

Chloro benzene is commercially prepared by passing a mixture of benzene vapour, air and HCl over heated cupric chloride .This reaction is called Raschig process.

3.10.           Properties

Melting and boiling points

The boiling points of monohalo benzene which are all liquids follow the order

Iodo > Bromo > Chloro

The boiling points of isomeric dihalobenzene are nearly the same

The melting point of para isomer is generally higher than the melting points of ortho and meta isomers. The higher melting point of p-isomer is due to its symmetry which leads to more close packing of its molecules in the crystal lattice and consequently strong intermolecular attractive force which requires more energy for melting

p -Dihalo benzene > o- Dichloro benzene > m-Dichloro benzene

Solubility

Haloarenes are insoluble in water because they cannot form hydrogen bonds with water ,but are soluble in organic solvents

Density

Halo arenes are all heavier than water and their densities follow the order.

Iodo benzene > Bromo benzene > Chloro benzene

Chemical properties

A. Reactions invoving halogen atom

1. Aromatic nucleophilic substitution reaction

Halo arenes do not undergo nucleophilic substitution reaction readily. This is due to C-X bond in aryl halide is short and strong and also the aromatic ring is a centre of high electron density.

The halogen of haloarenes can be substituted by OH- , NH2-, or CN- with appropriate nucleophilic reagents at high temperature and pressure.

For Example

This reaction is known as Dow’s Process

2. Reaction with metals

a) Wurtz Fittig reaction

Halo arenes reacts with halo alkanes when heated with sodium in ether solution to form alkyl benzene. This reaction is called Wurtz Fittig reaction.

b) Fittig reaction

Haloarenes react with sodium metal in dry ether, two aryl groups combine to give biaryl products. This reaction is called Fittig reaction

 

 

B)      Reaction involving aromatic ring

3. Electrophilic substitution reaction

Haloarenes undergo aromatic electrophilic substitution reactions. The rate of eleclophilic substitution of halobenzene is lower than that ofbenzene. halogen is deactivating due to - I effect of halogen. The lone pair of electrons on the chlorine involves in resonance with the ring. It increases the electron density at ortho and para position. The halogen attached to the benzine ring with draw electron and thereby and hence the halogen which is attached to the benzene directs the incoming, electrophile either to ortho or to para position in electrophilie substitution reaction

4) Reduction

Haloarenes on reduction with Ni- Al alloy in the presence of NaOH gives corresponding arenes.

5) Formation of Grignard reagent

Haloarenes reacts with magnesium to form Grignard reagent in tetra hydrofuran (THF).

3.11.            Uses

i)                Chloro benzene is used in the manufacture of pesticides like DDT

ii)              It is used as high boiling solvent in organic synthesis.

iii)            It is used as fibre - swelling agent in textile processing.

3.12.           Mechanism of nucleophilic aromatic substitution – benzyne intermediate.

we saw that electron-poor aromatic rings containing a leaving group can undergo substitution with electron-rich nucleophiles.  We saw that the mechanism proceeds through addition of a nucleophile to the aromatic ring (via an electron-rich intermediate) followed by loss of a leaving group, in a process sometimes called, “addition-elimination”.

Importantly, the only substitution product is the one where the nucleophile ends up attached to the same carbon as that bearing the leaving group.  (This differentiates it from electrophilic aromatic substitution, where a mixture of ortho-, para–  and meta- products can be obtained.)

2. A “Nucleophilic Aromatic Substitution” In Name, But by A Different Mechanism

Although the “addition-elimination” mechanism for nucleophilic aromatic substitution has been known since at least 1902, it became increasingly clear in the first half of the twentieth century that certain reactions classified as “nucleophilic aromatic substitution” appeared to proceed through a different mechanism altogether.

For example, it was found that treating chlorobenzene with sodium amide (NaNH2) in liquid ammonia (boiling point = –33°C) resulted in the rapid formation of aminobenzene (“aniline”):

An addition-elimination mechanism here doesn’t seem right, considering that nucleophilic aromatic substitution reactions with far stronger electron withdrawing groups (e.g. NO2, rather than Cl) require higher temperatures and longer reaction times.

Another observation was that no reaction occurred under these conditions when the ortho- positions were attached to alkyl groups. A hydrogen is necessary at one of these positions for the reaction to proceed.

(note – NaNH2 and KNH2 can be considered to be essentially the same for our purposes)

A second observation was that in the case below only the ortho- and meta- products formed, and never the para– .

3. The Benzyne Intermediate

Various intermediates were proposed to explain these results, but then in 1953 John D. Roberts (then at MIT) nailed it by publishing one of the most elegant chemical experiments of all time.

He and his team synthesized chlorobenzene but with a special difference: the carbon attached to the chlorine was a radioactive isotope of carbon (14C), not carbon (12C).

This radioactive carbon atom served as an atomic “label”, which allowed them to conclusively determine if substitution happened exclusively at the carbon bearing the leaving group.  

Roberts’ group carried out the reaction under conditions reported previously, and found that about 50% of the product ended up with the NH2 attached to the labelled carbon, and the other 50% had the NH2 on the carbon adjacent to the label.

This is not consistent with an addition-elimination mechanism!

In fact, the roughly 50:50 ratio of products implies the involvement of a symmetrical intermediate which is attacked equally on either side.Roberts’ proposal – which has stood the test of time – was the involvement of a short-lived intermediate bearing a carbon-carbon triple bond: “Benzyne”! 

At first glance, this seems crazy. A triple bond in an aromatic ring?

Well, it’s not quite a true triple bond in the way that we’re familiar with (i.e. with alkynes). Instead of an overlap between two 2p orbitals (as in an alkyne) the “triple bond” is formed through overlap of two adjacent sp2 orbitals in the plane of the ring (i.e. at right angles to, and completely independently of, the aromatic pi system).

Since these orbitals actually point away from each other, the overlap between them is poor, resulting in a “triple bond” that is actually very weak.

The strain energy of benzyne has been estimated to be about 50 kcal/mol – more strained than cyclopropane (28 kcal/mol), and only slightly less strained than cyclopropene (54 kcal/mol).

An intuitive way to think about it is to imagine the involvement of two resonance structures (far left and far right, below) that make strong (and equal) contributions to the overall resonance hybrid, such that both carbons can be considered “electrophilic”.

[A more rigorous way to treat it is from a molecular orbital perspective – a weak bond results in a low-energy LUMO, and therefore a lower energetic barrier to attack by nucleophiles]. 

However strange it might look, the benzyne intermediate explains all of these important observations, and more.

In the first step (elimination) a strong base removes a hydrogen from the carbon adjacent to that bearing the leaving group, resulting in an elimination reaction that forms the triple bond. This explains why no reaction occurs when both positions adjacent to the leaving group lack hydrogen!

  • In the second step (addition), attack of the can come at either side of the triple bond, resulting in about a 1:1 mixture of the product with NH2 attached to the labelled carbon (A) and NH2 adjacent to the labelled carbon (B).

Although it’s tempting to use NH2 as nucleophile, the more likely nucleophile here is the solvent, NH3, which readily reacts with the extremely reactive benzyne intermediate. After attack of NH3, proton transfer occurs to result in the neutral product. 

3.1. Aryl alkyl halides Nomenclature

Nomenclature of Haloalkanes

Alkyl halides are named in two ways. In the common system, the alkyl group is named first followed by the appropriate word chloride, bromide, etc. The common name of an alkyl halide is always written as two separate words.

In the IUPAC system, alkyl halides are named haloalkanes. The other rules followed in naming compounds is that

·        Select the longest chain of carbon atoms containing the halogen atom.

·        Number the chain to give the minimum number to the carbon-carrying halogen atom.

·        If multiple bonds (double or triple bonds) are present, then it is given the preference in numbering the carbon chain.

·        The IUPAC name of any halogen derivative is always written as one word.

Compound

Common Name

IUPAC Name

CH3-Cl

Methyl Chloride

Chloromethane

CH3-CH2-Br

Ethyl bromide

Bromoethane

CH3-C(CH3)2-Br

tert-Butyl bromide

2-Bromo-2-methylpropane

CHCl3

Chloroform

Trichloromethane

CH3-CH(Br)2

Ethylidene bromide

1,1-Dibromoethane

CH2=CH-CH2-I

Allyl iodide

3-Iodoprop-1-ene

Nomenclature of Haloarenes

  • Aryl halides are named by prefixing “halo” to the name of the parent aromatic hydrocarbon.
  • If there is more than one substituent on the ring then the relative positions of the substituents are indicated by mathematical numerals.
  • In the common system, the relative position of two groups is shown by prefixes ortho, meta or para.

The common and IUPAC names of some representative haloarenes are given below.

3.2.             Alcohols

Alcohol, an organic compound containing hydroxyl (-OH ) functional group. Many organic compounds containing –OH group play an important role in our body. For example, cholesteryl alcohol commonly known as cholesterol is an important component in our cell membrane. Retinol, the storage form of vitamin A, finds application in proper functioning of our eyes. Alcohols also find application in many areas like medicine, industry, etc., For example, methanol is used as an industrial solvent, ethyl alcohol an additive to petrol, isopropyl alcohol as a skin cleanser for injection, etc., The hydroxyl group of alcohol can be converted to many other functional groups.

Hence, alcohols are important resource in synthetic organic chemistry. In this unit, we will learn the preparation, properties and uses of alcohols, phenols and ethers.

3.3.             Nomenclature

Naming the organic compounds according to IUPAC guidelines

·       Select the longest continuous chain of carbon atoms (root word) containing the functional group ( -OH ).

·       Number the carbon atoms in the chain so that the carbon bearing the -OH group has the lowest possible number.

·       Name the substituent (if any)

·       Write the name of the alcohol as below.

Prefix + Root word +    Primary suffix         + Secondary suffix

(substituents) (longest chain) (Saturation /unsaturation) (ol)The following table illustrates the IUPAC nomenclature of alcohols.

3.4.              Classification

Alcohols can be classified based on the number of hydroxyl groups and the nature of the carbon to which the functional group (–OH) is attached.

3.5.              Preparation

1. From Alkyl halides: Alkyl halides on heating with dilute aqueous NaOH gives alcohols. Primary alkyl halides undergo substitution by SN2 reaction. Secondary and tertiary alkyl halides usually undergo nucleophilic substitution by SN1 mechanism.

If R =t-butyl,  the reaction proceeds through the formation of t-butyl carbocation

From alkenes: Addition of water across the double bond of an alkene in presence of concentrated sulphuric acid gives alcohols. This addition reaction follows Markownikoff’s rule.

From Grignard reagent: Nucleophilic addition of Grignard reagent to aldehydes/ketones in presence of dry ether followed by the acid hydrolysis gives alcohols. Formaldehyde gives primary alcohol and other aldehydes give secondary alcohols. Ketones give tertiary alcohols.

4. Hydroboration:

Diborane reacts with an alkene to form trialkyl borane which on treatment with H2O2 in presence of NaOH gives an alcohol. (Refer reactions of diborane) The overall reaction is hydration of an alkene. This reaction yields an anti-Markownikoff's product.

1)    Reduction of carbonyl compounds:

Reduction of aldehydes/ketones with LiAlH4 in the presence of solvents like THF (Tetrahydrofuran) followed by hydrolysis gives alcohols. Unlike other reducing agents such as Raney Ni, Na-Hg/H2O, the lithium aluminium hydride does not reduce the carbon-carbon double bond present in unsaturated carbonyl compound and hence it is a best reagent to prepare unsaturated alcohols.

 

3.6.             Properties

Physical properties

i.                Lower alcohols are colourless liquids and the higher members are waxy solids.

ii.              They have higher boiling points than the corresponding other organic compounds such as alkanes, aldehydes, ethers etc., this is due to the presence of intermolecular hydrogen bonding present in alcohols.

iii.            Among isomeric alcohols primary alcohols have higher boiling point and the tertiary alcohols have lower boiling points.

iv.             The lower members are highly soluble in water due to the formation of intermolecular hydrogen bonding with water.

Boiling point of alcohols in comparision with other organic compounds.

Chemical properties of alcohols

Nucleophilic substitution reactions of alcohols

Alcohol has a strong basic leaving group (OH-). So, -OH group is first converted into -OH2 group by adding an acid. The -OH2 group in the protonated alcohol can be easily displaced by a nucleophile such as Br- to give alkyl halides.

Example: Alcohols undergo nucleophilic substitution reaction with hydro halic acids to form alkyl halides. In case of tertiary alcohols heating is required.

2. Elimination reactions of alcohols

When alcohols are heated with a suitable dehydrating agents like sulphuric acid, the H and OH present in the adjacent carbons of alcohols are lost, and it results in the formation of a carbon - carbon double bond. Phosphoric acid, anhydrous ZnCl2, alumina etc., can also be used as dehydrating agents.

Mechanism

Primary alcohols undergo dehydration by E2 mechanism

Tertiary alcohols undergo dehydration by E1 mechanism. It involves the formation of a carbocation.

Protonation of alcohol

3.7.             Uses

Uses of methanol :

1. Methanol is used as a solvent for paints, varnishes, shellac, gums, cement, etc.

2. In the manufacture of dyes, drugs, perfumes and formaldehyde.

Uses of ethanol:

1. It is also used in the preparation of a)Paints and varnishes. b) Organic compounds like ether, chloroform, iodoform, etc., c)Dyes, transparent soaps.

2. As a substitute for petrol under the name power alcohol used as fuel for aeroplane

3. It is used as a preservative for biological specimens.

Uses of ethylene glycol:

1. Ethylene glycol is used as an antifreeze in automobile radiator

2. Its dinitrate is used as an explosive with TNG.

Uses of glycerol

1. Glycerol is used as a sweetening agent in confectionary and beverages.

2. It is used in the manufacture of cosmetics and transparent soaps.

3. It is used in making printing inks and stamp pad ink and lubricant for watches and clocks.

4. It is used in the manufacture of explosive like dynamite and cordite by mixing it with china clay

3.8.             Test for hydroxyl groups

The following tests are used to distinguish between 1°, 2° and 3° alcohols.

a) Lucas test:

When alcohols are treated with Lucas agent (a mixture of concentrated HCl and anhydrous ZnCl2) at room temperature, tertiary alcohols react immediately to form a turbidity due to the formation of alkyl chloride which is insoluble in the medium. Secondary alcohols react within 10 minutes to form a turbidity of alkyl chloride where primary alcohols do not react at room temperature.

b)  Victor Meyer’s test:

This test is based on the behaviour of the different nitro alkanes formed by the three types of alcohols with nitrous acid and it consists of the following steps.

i)   Alcohols are converted into alkyl iodide by treating it with I2/P .

ii)  Alkyl iodide so formed is then treated with AgNO2 to form nitro alkanes.

ii)  Nitro alkanes are finally treated with HNO2 (mixture of NaNO2 / HCl) and the resultant solution is made alkaline with KOH.

Result:

• Primary alcohol gives red colour

• Secondary alcohol gives blue colour.

• No colouration will be observed in case of tertiary alcohol.

3.9.             Oxidation of diols by periodic acid

Ethylene glycol on treatment with periodic acid gives formaldehyde. This reaction is selective for vicinal 1,2 – diols and it proceeds through a cyclic periodate ester intermediate.

3.10.           Oxidation of diols by lead tetraacetate.

The Criegee oxidation is a glycol cleavage reaction in which vicinal diols are oxidized to form ketones and aldehydes using lead tetraacetate. It is analogous to the use of periodate (Malaprade reaction) but uses a milder oxidant. This oxidation was discovered by Rudolf Criegee and coworkers and first reported in 1931 using ethylene glycol as the substrate.

Two mechanisms are proposed for the Criegee oxidation, depending on the configuration of the diol. If the oxygen atoms of the two hydroxy groups are conformationally close enough to form a five-membered ring with the lead atom, the reaction occurs via a cyclic intermediate. If the structure cannot adopt such a conformation, an alternate mechanism is possible, but is slower. Trans-fused five member rings are heavily strained, thus trans-diols that are on a five-membered ring will react slower than cis-alcohols on such a structure.

 

UNIT-V

4.   Phenols

Phenols are organic compounds in which a -OH group is directly attached to a benzene ring. The carbon bearing the -OH group is sp2 hybridized.

4.1.              Nomenclature;

4.2.             Preparation from diazonium salts

Aniline is diazotized with nitrous acid (NaNO2 +HCl ) at 273-278K to give benzene diazonium chloride which on further treatment with hot water in the presence of mineral acid gives phenol.

 

4.3.             Preparation from Cumene

A mixture of benzene and propene is heated at 523K in a closed vessel in presence of H3PO4 catalyst gives cumene (isopropylbenzene). On passing air to a mixture of cumene and 5% aqueous sodium carbonate solution, cumene hydro peroxide is formed by oxidation. It is treated with dilute acid to get phenol and acetone. Acetone is also an important byproduct in this reaction.

4.4.            Dow’s process

From halo arenes(Dows process)

When Chlorobenzene is hydrolysed with 6-8% NaOH at 300 bar  and 633K in a closed vessel,sodium phenoxide is formed which on treatment with dilute HCl gives phenol.

 

4.5.             Raching process;

Generally we call it the Raschig - Hooker process. This process is used for production of phenol. We use Rasching’s process for the preparation of chlorobenzene. After that we convert the obtained chlorobenzene to phenol by hydrolysis that is by adding water.

In the first step we convert the benzene into chlorobenzene. That is when benzene reacts with hydrochloric acid in the presence of oxygen we will get chlorobenzene. In this step we use either copper or iron chloride catalyst and we expose the material to air at 4000C

In step two we convert the obtained chlorobenzene into phenol by hydrolyses. In this step we expose the material (chlorobenzene) to a steam at 4500C

Phenol is a useful precursor to a huge collection of drugs, most notably aspirin but also several herbicides and pharmaceutical drugs. Phenol by-products have been used in the making of cosmetics including hair colouring, sunscreens and in skin lightening preparations.

4.6.             Properties

Physical Properties

Phenol is colourless, needle shaped crystal, hygroscopic, corrosive and poisonous. It turns pink on exposure to air and light. The simplest phenols are liquids or low melting solids, they have quite high boiling points. Phenol is slightly soluble in water because of hydrogen bonding. However other substituted phenols are essentially insoluble in water.

Chemical Properties:

Reactions involving -OH group.

a) Reaction with Zn dust:

Phenol is converted to benzene on heating with zinc dust. In this reaction the hydroxyl group which is attached to the aromatic ring is eliminated.

b) Reaction with ammonia:

Phenol on heating with ammonia in presence of anhydrous ZnCl2 gives aniline.

c)Formation of esters:

Schotten-Baumann reaction :

Phenol on treatment with acid chlorides gives esters. The acetylation and benzoylation of phenol are called Schotten-Baumann reaction.

d)Formation of ethers:

Williamson ether synthesis:

An alkaline solution of phenol reacts with alkyl halide to form phenyl ethers. The alkyl halide undergoes nucleophilic substitution by the phenoxide ion in the presence of alkali.

d) Oxidation:

Phenol undergoes oxidation with air or acidified K2Cr2O7 with conc. H2SO4 to form 1,4-benzoquinone.

e)Reduction:

Phenol on catalytic hydrogenation gives cyclohexanol.

4.7.             acidic character and effect of substitution on acidity.

Acidity of Phenol

Phenol is more acidic than aliphatic alcohols. Unlike alcohols it reacts with bases like sodium hydroxide to form sodium phenoxide. This explains the acidic behaviour of phenol.let us consider the aqueous solution of phenol in which the following equilibrium exists.

Ka value for the above equilibrium is 1×10-10 at 25oC. This Ka value indicates that it is more acidic than aliphatic alcohols. This increased acidic behaviour can be explained on the basis of the stability of phenoxide ion. We have already learnt in XI standard that the phenoxide is more stabilised by resonance than phenol.

In substituted phenols, the electron withdrawing groups such as -NO2, -Cl enhances the acidic nature of phenol especially when they are present at ortho and para positions. In such cases, there is a possibility for the extended delocalisation of negative charge on the phenoxide ion. On the otherhand the alkyl substitued phenols show a decreased acidity due to the electron releasing +I effect of alkyl group.

Table: pKaValues of some alcohols and phenols

S.No.

Compound

pKa Value

1

methanol

15.5

2

ethanol

15.9

3

propan - 2- ol

16.5

4

2 - methyl propan 2 - ol

18.0

5

Cyclohexanol

18.0

6

Phenol

10.0

7

o - nitrophenol

7.2

8

p - nitrophenol

7.1

9

m - nitrophenol

8.3

10

o - cresol

10.2

11

m - cresol

10.1

12

p - cresol

10.2

 

4.8.             Fries Rearrangement

·        Fries Rearrangement is an organic rearrangement reaction in which an aryl ester is transformed into a hydroxy aryl ketone with the help of a Lewis acid catalyst and an aqueous acid.

·         In this reaction, an acyl group belonging to the phenolic ester migrates to the aryl ring.

·         It is important to note that Fries rearrangement is ortho and para selective, i.e. the acyl group attaches itself at the ortho or para positions of the aryl ring. 

·        The selectivity of the reaction can be directed by modifying the reaction conditions (such as the temperature under which the reaction is conducted, or the solvent used in the reaction).

An illustration detailing the Fries rearrangement undergone by phenyl acetate (acetoxy benzene) is provided above. Note that the products feature ortho and para migrations of the acyl group.

Fries Rearrangement Mechanism

Initially, the carbonyl oxygen belonging to the acyl group forms a complex with the Lewis acid catalyst (usually AlCl3). The formation of the complex with the carbonyl oxygen is favoured over the complexation of the phenolic oxygen since the carbonyl oxygen is richer in electrons and is, therefore, a better Lewis base.

Now, the bond between the phenolic oxygen and the acyl complex becomes polarised, resulting in the rearrangement of the AlCl3 bond to the phenolic oxygen. This results in the generation of an acylium carbocation.

The acylium carbocation goes on to attack the aromatic ring via an electrophilic aromatic substitution reaction. It is important to note that the orientation of this electrophilic aromatic substitution is temperature-dependent. Low reaction temperatures favour substitutions at the para position and relatively high temperatures favour ortho substitution.

The mechanism of the Fries rearrangement reaction is illustrated above. The use of a non-polar solvent in this reaction also favours the formation of ortho-substituted products. Highly polar solvents favour para substitution in this reaction.

  • Limitations of Fries Rearrangement

The key limitations of Fries rearrangement are listed below.

  • Owing to its relatively harsh reaction conditions, only esters with relatively stable acyl components can be used in this reaction.
  • Low yields are obtained when heavily substituted acyl components exist.
  • The presence of deactivating or meta-directing groups on the aromatic ring results in low yields.

4.9.              Claisen rearrangement

Claisen rearrangement is an organic chemical reaction that offers a powerful method of the formation of carbon-carbon bonds. The reactant of this reaction – allyl vinyl ether, is converted into a gamma, delta-unsaturated carbonyl compound when subjected to heat or a Lewis acid.

The Claisen rearrangement reaction is named after its discoverer, the German chemist Rainer Ludwig Claisen, who discovered it in 1912. This reaction belongs to the “sigmatropic rearrangement” category of reactions wherein the mechanism of the reaction is concerted (i.e. all the bonds break and form simultaneously).

An interesting fact about this reaction is that it was the first ever recorded example of a [3,3]- sigmatropic rearrangement reaction.

An example of the Claisen rearrangement reaction of an allyl vinyl ether is given below.

Claisen Rearrangement Reaction

The reaction can also be performed with allyl phenyl ethers. In this rearrangement, the regio selectivity is affected by the meta-substitution. The [3,3]-sigmatropic rearrangement of the allyl phenyl ether gives an intermediate. This intermediate now undergoes tautomerization to give a phenol which is substituted at the ortho position. An example for the [3,3]-sigmatropic rearrangement of an allyl phenyl ether is given below.

Mechanism of Claisen Rearrangement

This rearrangement reaction has an exothermic nature. As discussed earlier, the reaction mechanism is concerted. The reaction kinetics of this rearrangement reaction is of the first order. The reaction is accelerated by polar solvents. Hydrogen-bonding solvents provide further acceleration of reaction speed and greater rate constants.

1. Allyl Vinyl Ethers

Here, heat is the catalyst of the reaction. When the allyl vinyl ether is subjected to heat, it forms a transition state. Now, a [3,3]-sigmatropic rearrangement takes place leading to the formation of the required gamma, delta-unsaturated carbonyl compound product.

This mechanism is illustrated below.

2. Allyl Phenyl Ethers

The electrons are pushed around the six-membered ring in an electrocyclic process. The resulting dienone now undergoes tautomerization to give its aromatic enol form. This form is more stable than the dienone form. The required compound is therefore formed.

This mechanism can be illustrated as follows.

ELECTROPHILIC SUBSTITUTION REACTIONS

4.10.          Reimer – Teimen Reaction

On treating phenol with CHCl3/NaOH, a -CHO group is introduced at ortho position. This reaction proceeds through the formation of substituted benzal chloride intermediate.

4.11.           Kolbe-Schmidt Reaction

In this reaction, phenol is first converted into sodium phenoxide which is more reactive than phenol towards electrophilic substitution reaction with CO2 . Treatment of sodium phenoxide with CO2 at 400K, 4-7 bar pressure followed by acid hydrolysis gives salicylic acid.

4.12.           Gatermann synthesis

Formylation of aromatic substrates like benzene, phenol or ether on reaction with hydrogen cyanide and gaseous hydrochloric acid in the presence of anhydrous aluminium chloride or zinc chloride is known as Gattermann aldehyde synthesis. Zinc chloride with HCN and HCl forms zinc cyanide.

EXAMPLE:1

EXAMPLE:2

 

Mechanism

1.Formation of formiminochloride aluminium chloride intermediate by the action ofAlCl3 on HCN and HCI (a).

2. Electrophilic reaction of the intermediate on aromatic compound leads to the formation of cationic intermediate (b).

3. Deprotonation and aromatisation forming iminoformyl hydrochloride (c).

4. Hydrolysis of the product (c) to get aldehyde.

4.13.           Libermann reaction

While phenol is reacted with NaNO2 and concentrated H2SO4, it provides a deep green or blue colour which changes to red on dilution with water. while generated alkaline along with NaOH original green or blue colour is restored. This reaction is termed as Liebermann's nitroso reaction and is employed as a test of phenol.

 

4.14.          phthalein reaction

On heating phenol with phthalic anhydride in presence of con.H2SO4, phenolphthalein is obtained.

4.15.           Resorcinol

Resorcinol compound consists of elements Carbon, Hydrogen, and Oxygen. Carbon is a nonmetal present in group-14 of the periodic table. Its atomic number is 6 and is represented with the symbol C. Hydrogen is a colorless, odorless, tasteless, and flammable gas. Its atomic number is 1 and is represented with the symbol H. Oxygen is a highly reactive nonmetal and a good oxidizing agent. It is present in the chalcogen group of the periodic table. Its atomic number is 8 and is represented by the symbol O.

Resorcinol Formula 

Resorcinol is a white crystalline solid organic compound with a faint odor and sweetish to bitter taste. Its chemical formula is C6H6O2. It is soluble in water, alcohol, and ether, but it doesn’t dissolve Chloroform and Carbon disulfide. It is difficult to ignite. C6H6O2 is one of the three isomeric benzenediols. It is a 1,3-isomer of benzenediol, i.e., benzene dihydroxylated at 1 and 3 positions. The other names of Resorcinol are Resorcin, 3-Hydroxyphenol, m-Benzenediol, and m-Dihydroxybenzene. Resorcin doesn’t occur naturally in a free state but is found in argan oil. It turns into pink color on exposure to air and light.

Preparation of Resorcinol

Resorcinol crystallizes from benzene as colorless needles. Resorcinol is prepared by a classic sulfonate fusion process. Firstly benzene is treated with sulfuric acid at 100°C, which gives mono sulfonic acid. It is converted into m-disulfonic acid with 65% oleum at 85°C. Now m-Benzenedisulfonate melts in Sodium Hydroxide(NaOH) at 300 °C to give Resorcinol and Sodium sulfite. 

Structure of Resorcinol

Physical Properties of Resorcinol

  • Resorcinol appears in white solid form.
  • Odor of Resorcinol is a faint Benzene odor.
  • The molecular weight of Resorcinol is 110.1 g/mol.
  • The melting point of Resorcinol is 110°C.
  • Its boiling point is 277°C.
  • The density of Resorcinol is 1.28 g/cm3.

Chemical Properties of Resorcinol

  • Resorcinol (C6H6O2) on partial hydrogenation gives Dihydroresorcinol (C6H8O2), which is also known as 1,3-cyclohexanedione.
  • Sodium amalgam (NaHg) reduces Resorcinol (C6H6O2) to dihydro resorcinol (C6H8O2). The resultant is heated to 150 to 160 °C with a concentrated barium hydroxide solution to give γ-acetylbutyric acid (C6H10O3).
  • Resorcinol reduces Fehling’s solution and ammoniacal silver solutions.

 Uses of Resorcinol

  • Resorcinol is used as a sensitizer and an erythropoietin inhibitor.
  • It is used in the production of resins.
  • Resorcinol is widely used in the making plastics and pharmaceuticals.
  • It is used as an intermediate in the synthesis of organic compounds.
  • Resorcinol is used in the treatment of acne.
  • It is a disinfectant and analytical reagent.

 

4.16.           Quinol

The chemical formula for hydroquinone (Quinol) is C6H6(OH)2𝐶6𝐻6(𝑂𝐻)2. It is a crystalline solid at room temperature. The crystal structure of hydroquinone is monoclinic. The unit cell contains 4 molecules composed of two and two not dependent on space group symmetry.

Let's take a look at the structure of deprotonated hydroquinone. A deprotonated hydroquinone has one hydrogen atom missing. 

 The resonance structures for this compound are- 

Hydroquinone can be prepared in two main methods at a large scale, these methods are-

The first method is quite similar to the cumene method, in this benzene undergoes dialkylation reaction with propene and produces 1,4-diisopropyl benzene. 1,4-diisopropylbenzene, reacts with air to produce bishydroperoxide, it has structure similar to cumene hydroperoxide. Bishydroperoxide rearranges itself in the presence of acid to yield hydroquinone and acetone. 

The second method proceeds by the hydroxylation of phenol in the presence of a catalyst. Hydrogen peroxide is used in the reaction and a mixture of hydroquinone and catechol is produced. The chemical reaction for the preparation of hydroquinone is as follows- 

C6H5OH + H2O2 → C6H4(OH)2+H2O𝐶6𝐻5𝑂𝐻 + 𝐻2𝑂2 

𝐶6𝐻4(𝑂𝐻)2+𝐻2𝑂

Hydroquinone uses 

  • It is commonly used as a reducing agent. 
  • It is used as a biomarker for benzene exposure
  • It is used by photographic developers.
  • It is used to treat acne scarring.
  • It is used in skin lightening and whitening creams.
  • It finds application in photographic film and paper. 
  • It is used as a polymerization barrier.
  • It finds its application as a preservative for resins and improves its shelf life.
  • It acts as a biomarker in benzene exposure.

 

4.17.           picric acid

Properties of Picric Acid

It’s chemical structure consists of a benzene ring with three nitro groups (-NO2) attached to it. Picric acid is highly explosive and can be toxic if handled improperly. 

Physical Properties of Picric Acid

The physical properties of picric acid are mentioned below:

  • Picric acid, also known as 2,4,6-trinitrophenol, is a yellow crystalline solid at room temperature.
  • It has a distinct odor, often described as similar to bitter almonds.
  • Picric acid is sparingly soluble in water but dissolves well in organic solvents like ethanol and ether.
  • It is highly explosive when dry and can detonate upon impact or friction.
  • The compound is sensitive to heat and shock, making it hazardous to handle.
  • Picric acid is commonly used in the manufacture of dyes, explosives, and as a reagent in chemical laboratories.
  • It can form sensitive and unstable compounds with metals like lead, copper, and iron, increasing its risk of detonation.
  • Exposure to picric acid, especially through inhalation or skin contact, can cause irritation, burns, and other health hazards.

Chemical Properties of Picric Acid

The chemical properties of picric acid are mentioned below:

  • Picric acid is a yellow yet crystalline compound.
  • It is one of the most exhaustive ideal gases, and thus, even in small quantities, it is highly dangerous.
  • It can form solution in both, water and many organic solvents.
  • Picric acid, is generally applied in the setting up of dyes, metalutic substances(explosives) and as a reagent in chemical.
  • It has a tendency to be ‘troublemaker’ reacting violently with metals, bases, and reducing agents.
  • This exhibits its characteristisc when heated, can decompose violently.
  • The corrosion on skin or eyes can be very dangerous and can lead to severe burns.
  • Its strong reactive power makes it rated thus caution is required when handling and therefor storage.

Preparation of Picric Acid

The method of preparation of picric acid is discussed below:

Formation of Phenol Sulphuric Acid:

First, phenol is mixed with concentrated sulfuric acid. This mixture is gently heated. During this reaction, sulfuric acid acts as a catalyst, facilitating the formation of phenol sulfate.

Nitration Reaction:

In the second step, the phenol sulfate formed in the previous step is further treated with concentrated nitric acid.

Nitric acid introduces nitro groups (NO2) onto the phenol ring. These nitro groups preferentially attach themselves to the ortho and para positions of the phenol ring due to electronic effects, resulting in the formation of 2,4,6-trinitrophenol, which is picric acid.

 

Uses of Picric Acid

The uses of picric acid are mentioned below:

  • Picric acid and its derivatives like Dunnite and TATB are common explosives.
  • Picric acid, especially as Picral, has been used in metallurgy, but its use is declining due to risks.
  • Picric acid is used in organic chemistry to create picrates, aiding in identification.
  • Bouin solution, containing picric acid, enhances histology staining but may cause DNA hydrolysis.
  • Picric acid reacts with hydrogen cyanide to produce red isopurpurate for cyanide quantification.
  • Picric acid was used in early 20th-century hospitals as an antiseptic and for various treatments.
  • Picric acid historically measured blood glucose levels using the Lewis and Benedict system.
  • Picric acid has been used in fly tying to dye materials for fishing lures, despite toxicity concerns.

4.18.           Aromatic alcohols Nomenclature

STRUCTURE

NAME

4-Fluoro-2-methylphenol

2-Chlorobenzyl alcohol

3-Bromobenzyl alcohol

4-Bromobenzyl alcohol

 

4.19.           Benzyl alcohol

Benzyl alcohol with the chemical formula C6H5CH2OH is an aromatic alcohol. The "Bn" group of benzyls is often abbreviated (not to be mistaken with "Bz" used for benzoyl), and benzyl alcohol is referred to as BnOH. Benzyl alcohol is a colourless liquid with a faint aromatic scent. Its polarity, low toxicity, and low vapour pressure make it a useful solvent. Benzyl alcohol has modest water solubility (4 g/100 mL), and alcohol and diethyl ether are miscible. The anion formed by alcohol group deprotonation is called benzylate, or benzyl oxide.

IUPAC Name: Phenyl methanol

Synonyms:Phenylcarbinol, Benzenemethanol

Chemical Formula:  C7H8O

METHODS OF PREPARATION

4.20.          HYDROLYSIS

Obtained by the chlorination of Toluene followed by hydrolysis with aqueous NaOH.

The formation of benzyl alcohol from benzyl chloride involves nucleophilic substitution.

This method is used in the large scale preparation of benzyl alcohol.

4.21.           Reduction of benzaldehyde

Phenylmethanol can be prepared from benzaldehyde by treating it with zinc in presence of HCl

This is categorised as a reduction reaction as hydrogen is added to the molecule during this reaction.

Given below is the chemical reaction for the same.

4.22.          Cannizzaro reaction

In the presence of concentrated aqueous or alcoholic alkali, aldehydes which do not have α - hydrogen atom undergo self oxidation and reduction (disproportionation) to give a mixture of alcohol and a salt of carboxylic acid. This reaction is called Cannizaro reaction.

Benzaldehyde on treatment with concentrated NaOH (50%) gives benzyl alcohol and sodium benzoate.

This reaction is an example disproportionation reaction

Crossed Cannizaro reaction

When Cannizaro reaction takes place between two different aldehydes (neither containing an α hydrogen atom), the reaction is called as crossed cannizaro reaction.

In crossed cannizaro reaction more reactive aldehyde is oxidized and less reactive aldehyde is reduced.

 

4.23.          Grignard synthesis

 

4.24.         Physical properties

It is a colourless pleasant smelling liquid with b.p. 478 K. It is sparingly soluble in water, because of the presence of hydrophobic phenyl group (larger in size when compared to methyl or ethyl group). But it is soluble in organic solvents like benzene and alcohol.

Chemically it resembles aliphatic primary alcohol. 1. It is not so acidic as to dissolve in sodium hydroxide but reacts with sodium metal forming sodium benzylate or sodium benzoxide.

Sodium benzoxide brings about nucleophilic substitution at methyl carbon atom of the methyl iodide forming ethers.

2. Reagents like PCl5, SOCl2 and HCl readily forms benzyl chloride with benzyl alcohol.

4. On heating with phosphorous and hydriodic acid, it is reduced to Toluene. Benzyl iodide is the intermediate in this reaction.

Iodine is removed by phosphorous.

Hydrogen in presence of Palladium is the other reagent that can reduce benzyl alcohol to Toluene.

5. Benzyl alcohol forms esters with carboxylic acids in presence of conc. sulphuric acid, and also with acid chlorides and acid anhydrides.

6. Oxidation : (i) With mild oxidising agents like copper nitrate or lead nitrate, benzyl alcohol is converted to benzaldehyde.

Decomposition of the metallic nitrate provide the source for the above oxidation.

(ii) In the oxidation with acidified potassium dichromate or alkaline potassium permanganate, benzaldehyde is first formed which undergoes further oxidation to benzoic acid.

7. In addition to the above reactions, it undergoes reactions characteristic of the benzene ring-namely electrophilic substitution reactions like halogenation, nitration, sulphonation etc. In all these cases substitution takes place in the benzene ring. Like CH3- and CH2C1- groups, CH2OH- is also ortho, para directing group. Hence ortho or para substituted products are formed.

 

Uses

(i) Used as a local anaesthetic in intravenus subcutaneous injections.

(ii) as an antiseptic in ointments.

(iii) as esters in perfumery. (Benzyl acetate has fragrance of Jasmine)

(iv) as benzyl benzoate in the treatment of asthma and whooping cough.

(v) in the manufacture of synthetic resins.

4.25.          Thiols

Thiols are often called “mercaptans,” a reference to the Latin term mercurium captans (capturing mercury), since the -SH group forms strong bonds with mercury and its ions. Thiols are analogous to alcohols. Thiols are weakly acidic (pKa ~ 10) and are much stronger acids than alcohols (pKa ~ 16). However, thiols usually do not form hydrogen bonds due to the sulfur atom not have sufficient electronegativity. Thiols named using the same rules as alcohols except the parent chain is named as alkane with the suffix -thiol added. As a substituent the -SH group is called a mercapto group.

Thiols are usually prepared by using the hydrosulfide anion (-SH) as a nucleophile in an SN2 reaction with alkyl halides.

One problem with this reaction is that the thiol product can deprotonate and undergo a second SN2 reaction with an additional 

alkyl halide to produce a sulfide side product. This problem can be solved by using thiourea, (NH2)2C=S, as the nucleophile. The SN2 reaction first produces an alkyl isothiourea salt as an intermediate. This salt is then hydrolyzed to form the thiol by a reaction with aqueous base.

Preparation of Thiols

Thiols are prepared by the nucleophilic substitution reaction where hydrosulfide anion is a nucleophile which reacts with alkyl halides.

For example- Reaction of sodium hydrosulfide with alkyl halides.

Hydrosulfide is used in excess amounts to prevent the reaction of thiol with the alkyl halide and the formation of sulphide and thioether due to its high nucleophilicity.

One more reaction uses alkyl halides with thiourea as a sulphur nucleophile. This reaction produces alklisohiouronium salts which are later hydrolyzed to thiols.

In this reaction, the lone pair of sulphur attacks on the alkyl group of bromoalkane and the alkyl bromide bond is broken. Then s-alklisothiouronium bromide is reacted with sodium hydroxide. The intermediate is then made to react with hydronium ions in the presence of sodium hydroxide. Therefore, the formation of thiol takes place.

Properties of Thiol

The physical and chemical properties of thiol are as follows-

Physical Properties 

  • They are colourless liquids.
  • Their odour is similar to that of garlic.
  • They have low boiling points.
  • They are less soluble in water and other polar solvents.
  • Thiol is responsible for the characteristic fragrance of grapefruit.

Chemical Properties 

The reaction of thiol with bromine yields organic disulfides. The reaction takes place as follows-

2R−SH + Br2 →R−S−S−R + 2HBr

2𝑅𝑆𝐻 + 𝐵𝑟2𝑅𝑆𝑆𝑅 + 2𝐻𝐵𝑟

Oxidation of thiols with powerful oxidising agents sodium hypochlorite or hydrogen peroxide yields sulphonic acids. The reaction proceeds as follows-

R−SH + 3H2O2 →RSO3H + 3H2O


 

GENERAL CHEMISTRY-III

Model Question Paper

SECTION A – (10 × 2 = 20 marks)

Answer ALL questions

1. Define Boyle’s temperature.

2. What is RMS velocity.

3. Define liquid crystals.

4. State laws of crystallography.

5. Define Nuclear binding energy.

6. What are radioactive series.

7. What is nucleophilic substitution reaction.

8. Give the reason why benzene will not undergoes nucleophilic substitution reaction.

9. Write the reaction of nitration of phenol.

10. What is catalysis hydrogenation.

SECTION B – (5 × 5 = 25 marks)

Answer ALL questions

11. A)Discuss the Maxwell distribution of molecular velocities  (or)

B) Derive the kinetic gas equation.

12. A) What is mean by seven crystal system. Explain in detail.

(or)

B) What are liquid crystals? How are they classified.

13. A) Difference between Nuclear fission and Nuclear fusion   (or)

B) What are the types of nuclear reactions? Give example.

14. A) Explain the mechanism of SN1 reaction.   (or)

B) Describe the Aromatic Nuclear Substitution reaction with example

15. A) Briefly explain the acidic character of phenol   (or)

B) Write the notes on I) Remer Tiemann reaction II) Houben Hoesh reaction.

SECTION C – (3 × 10 = 30 marks)

Answer any THREE questions

16. A) What is mean by viscosity and surface tension. What is the effect of temperature on it.

B) Write notes on liquid crystals.

17. Write the notes on Bravis Space lattice.

18. Write an account on application of Nuclear Chemistry.

19. Write preparation, properties and uses of Benzyl chloride.

20. Briefly explain the following reactions

I) Kolbe’s reaction.

II) Gatterman reaction.

III) Claisen rearrangement.

IV) Cannizaro reaction.

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